Don't miss your chance to take the Fabric Data Engineer (DP-700) exam on us!
Learn moreWe've captured the moments from FabCon & SQLCon that everyone is talking about, and we are bringing them to the community, live and on-demand. Starts on April 14th. Register now
This code works for me fine but as I can not hard code n and i would know it from "some other code" how would I make this into a loop that would run n times?
//some other code
in
result1,
a = Query1{0}[list],
b = Query1{1}[list],
......
n = Query1{n}[list]
c = List.Combine({a,b,...n})
in
c
Solved! Go to Solution.
What about this? Just change Number 100 to your n value - it can be stored also in [Column1] for example, so replace 100 with [Column1] if you add this as custom column.
= List.Combine(List.Transform({0..100}, (n)=> Query1{n}[list]))
What about this? Just change Number 100 to your n value - it can be stored also in [Column1] for example, so replace 100 with [Column1] if you add this as custom column.
= List.Combine(List.Transform({0..100}, (n)=> Query1{n}[list]))
just realized that my n is in //some other code and not accessible in that part of the code
it is inside Query1
If you have recently started exploring Fabric, we'd love to hear how it's going. Your feedback can help with product improvements.
A new Power BI DataViz World Championship is coming this June! Don't miss out on submitting your entry.
Share feedback directly with Fabric product managers, participate in targeted research studies and influence the Fabric roadmap.
| User | Count |
|---|---|
| 5 | |
| 4 | |
| 3 | |
| 3 | |
| 2 |
| User | Count |
|---|---|
| 8 | |
| 8 | |
| 6 | |
| 6 | |
| 5 |