Forum Discussion
Duplicates using Date and Duplicate/Original Slicer
Hi all, I would like to implement two slicers on a table similar to the one below. One for date and the other one for duplicates. For example, if the Duplicate/Original slicer says "Original" and Date Slicer says "01-01-2022" to "07-01-2022" the visual should show "3" and if the Duplicate/Original says "Duplicate" in the same date range, the visual should show 4. Thanks.
Hi, ashu710
Try this:result = VAR _originalValues = DISTINCTCOUNT( yourTable[valuesColumn] ) VAR _duplicateValues = COUNT( yourTable[valuesColumn] ) - _originalValues VAR _if = SWITCH( TRUE(), SELECTEDVALUE( 'theTable'[Slicer] ) = "Original", _originalValues, SELECTEDVALUE( 'theTable'[Slicer] ) = "Duplicate", _duplicateValues ) RETURN _ifBest Regards,
Community Support Team _ Zeon ZhengIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
3 Replies
- v-angzheng-msftCommunity Support
Hi, ashu710
Try this:result = VAR _originalValues = DISTINCTCOUNT( yourTable[valuesColumn] ) VAR _duplicateValues = COUNT( yourTable[valuesColumn] ) - _originalValues VAR _if = SWITCH( TRUE(), SELECTEDVALUE( 'theTable'[Slicer] ) = "Original", _originalValues, SELECTEDVALUE( 'theTable'[Slicer] ) = "Duplicate", _duplicateValues ) RETURN _ifBest Regards,
Community Support Team _ Zeon ZhengIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- BA_PeteSuper User
Wow, didn't fancy waiting a few hours for your answer on the other thread, huh?
I'll close off the old thread as you now have this one open as well.
FWIW, I'd be interested to know why you need to add this amount of complexity into your reporting when 99% of the time just displaying the two measures I gave you in the other thread would more than suffice.
Pete
- ashu710Frequent Visitor
Hi BA_Pete there's reporting that needs to be done on an urgent basis. I had already presented the solution you sent to my manager, and he thought that this would be an ideal solution. A few more calculations would be based off those measures, which I am unable to present using the given solution. Thanks.
Ashu