Forum Discussion
Date Difference with Filters
- 3 years ago
Hi Anonymous ,
You just need one measure for all of your requirements:
_projectLeadTime = AVERAGEX( SUMMARIZE( yourTable, yourTable[Project No.], "minStart", MIN(yourTable[Start Date]), "maxEnd", MAX(yourTable[End Date]) ), DATEDIFF([minStart], [maxEnd], DAY) )Here's the output when applied against different levels of dimensions:
Pete
Project No. | Task Lead Time | Project Lead Time |
AB10001 | 12 | 14 |
AB10001 | 12 | 14 |
AB10001 | 11 | 14 |
AB10001 | 11 | 14 |
AB10001 | 12 | 14 |
AB10002 | 43 | 74 |
AB10002 | 43 | 74 |
AB10002 | 41 | 74 |
AB10002 | 11 | 74 |
AB10002 | 12 | 74 |
AB10003 | 43 | 111 |
AB10003 | 43 | 111 |
AB10003 | 10 | 111 |
AB10003 | 72 | 111 |
AB10003 | 78 | 111 |
- NikhilChenna3 years agoSkilled Sharer
Hi Anonymous ,
I think you can simply do a summarize table of the above table i tried it my self with the below code, you have to replace the table name ,
For creating a table, you have to go to the modelling tab and click on the new table as shown below,
Summarized_table5 =SUMMARIZE('Table (5)','Table (5)'[Project No.],"Max Start date",MAX('Table (5)'[Start Date]),"Max End date",MAX('Table (5)'[End Date] ))After this you can simply add a calculated column , Lead time -Lead time = Summarized_table5[Max End date]-Summarized_table5[Max Start date]You' ll be able to see individual how much time did they took project wise and if you total all three lead time values you'll get the combined number for it.Regards,
Nikhil Chenna
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Did I answer your question? Mark my post as a solution!- NikhilChenna3 years agoSkilled Sharer
Hi Anonymous , If this solves your issue.
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- Anonymous3 years agoNot applicable
So as far as task is concern, the lead time is simple, start date - end date difference. But when it comes to project. I need the Difference between The date of latest end task & date of earliest started task. And finally after this, I need to view the total average of 3 Project, Not as Line 1+2+3...+15 and divide by 15,