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Create column with other column titles
Hi all I'm new to PQ and M-Code. I want to create a new column. It should store the name of other columns, depending on the data inside these other columns. Columns are oldest to newest...
Try with this code. One way to sort out the issue
update: I sligthly change the code to meet your requirements. You are not ooking for the max value.
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlXSUTIDYnOlWJ1oJUsgyxiITcA8QwMg0wjENzSCCFiABECiSrGxAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"2020/1" = _t, #"2020/2" = _t, #"2020/3" = _t]), #"Added Index" = Table.AddIndexColumn(Source, "Index", 0, 1, Int64.Type), #"Unpivoted Other Columns" = Table.UnpivotOtherColumns(#"Added Index", {"Index"}, "Attribute", "Value"), #"Filtered Rows1" = Table.SelectRows(#"Unpivoted Other Columns", each [Value] <> null and [Value] <> ""), #"Grouped Rows" = Table.Group(#"Filtered Rows1", {"Index"}, {{"Max", each List.Max([Attribute]), type text}, {"Rows", each _, type table [Index=number, Attribute=text, Value=text]}}), #"Added Index for columns names" = Table.TransformColumns( #"Grouped Rows", {"Rows", each Table.AddIndexColumn(_, "I")}), #"Expanded Rows" = Table.ExpandTableColumn(#"Added Index for columns names", "Rows", {"Attribute", "I", "Value"}, {"Attribute", "I", "Value"}), #"Filtered Rows - hold max" = Table.SelectRows(#"Expanded Rows", each [Max] = [Attribute]), #"Merged Queries Added Index withfiltered rows" = Table.NestedJoin(#"Added Index", {"Index"}, #"Filtered Rows - hold max", {"Index"}, "Filtered Rows", JoinKind.LeftOuter), #"Expanded Filtered Rows" = Table.ExpandTableColumn(#"Merged Queries Added Index withfiltered rows", "Filtered Rows", {"I"}, {"I"}), #"Added Columns Names" = Table.AddColumn(#"Expanded Filtered Rows", "Names", each Table.ColumnNames(Source){[I]}), Cleanup = Table.RemoveColumns(#"Added Columns Names",{"Index", "I"}) in Cleanup
latimeria
Solution Specialist
Solution SpecialistTry with this code. One way to sort out the issue
update: I sligthly change the code to meet your requirements. You are not ooking for the max value.
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlXSUTIDYnOlWJ1oJUsgyxiITcA8QwMg0wjENzSCCFiABECiSrGxAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"2020/1" = _t, #"2020/2" = _t, #"2020/3" = _t]),
#"Added Index" = Table.AddIndexColumn(Source, "Index", 0, 1, Int64.Type),
#"Unpivoted Other Columns" = Table.UnpivotOtherColumns(#"Added Index", {"Index"}, "Attribute", "Value"),
#"Filtered Rows1" = Table.SelectRows(#"Unpivoted Other Columns", each [Value] <> null and [Value] <> ""),
#"Grouped Rows" = Table.Group(#"Filtered Rows1", {"Index"}, {{"Max", each List.Max([Attribute]), type text}, {"Rows", each _, type table [Index=number, Attribute=text, Value=text]}}),
#"Added Index for columns names" = Table.TransformColumns( #"Grouped Rows", {"Rows", each Table.AddIndexColumn(_, "I")}),
#"Expanded Rows" = Table.ExpandTableColumn(#"Added Index for columns names", "Rows", {"Attribute", "I", "Value"}, {"Attribute", "I", "Value"}),
#"Filtered Rows - hold max" = Table.SelectRows(#"Expanded Rows", each [Max] = [Attribute]),
#"Merged Queries Added Index withfiltered rows" = Table.NestedJoin(#"Added Index", {"Index"}, #"Filtered Rows - hold max", {"Index"}, "Filtered Rows", JoinKind.LeftOuter),
#"Expanded Filtered Rows" = Table.ExpandTableColumn(#"Merged Queries Added Index withfiltered rows", "Filtered Rows", {"I"}, {"I"}),
#"Added Columns Names" = Table.AddColumn(#"Expanded Filtered Rows", "Names", each Table.ColumnNames(Source){[I]}),
Cleanup = Table.RemoveColumns(#"Added Columns Names",{"Index", "I"})
in
Cleanup
AlexisOlson
Super User
Super UserThis is solid logic. I think you can streamline it by dropping your [Rows] column entirely in the Group By though. Your [Max] column should already have the latest month and you can skip straight to the merge.