Forum Discussion
Convert Date to specific text format without creating new column
Hi,
I would find the syntax to convert an existing Date column into text, in the "dd/MM/yyyy" format, but do within the column, not by adding a new column. Using Date.ToText([Start Date], "dd/MM/yyyy") as the conversion code.
Tried using Transform and Change Type on the column and edit the resulting code, but keep getting an error, so must not have the syntax correct.
Cheers
- Anonymous6 years ago
PQ is very sensitive to Date versus DateTime. Sometimes i have to convert to a DateTime. Below is some sample code.
Regards,
Mike
let Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content], #"Extracted Date" = Table.TransformColumns(Source,{{"myDate", each Date.ToText(Date.From(_),"dd/MM/yyyy") , type text}}) in #"Extracted Date"
10 Replies
- Nathaniel_CCommunity Champion
Hi PhilC ,
My standard date is mm/dd/yyyy. So: the first pic is date, second pic is text. Included is the code, but what I did was go to Date Type, and change it to text.
Let me know if you have any questions.
If this solves your issues, please mark it as the solution, so that others can find it easily. Kudos are nice too.
Nathaniel- PhilCResolver I
Hi Nathaniel,
My dates are not currently formatted, so I have M and MM dates. I need to have dd/MM/yyyy as I am going to compare to another dateset on a text basis, so am looking to have a consistent text format.
I have tried using Change Type on the column but it does not alter for format to expand M to MM with a preceeding 0, which is what I need.
- AnonymousNot applicable
PQ is very sensitive to Date versus DateTime. Sometimes i have to convert to a DateTime. Below is some sample code.
Regards,
Mike
let Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content], #"Extracted Date" = Table.TransformColumns(Source,{{"myDate", each Date.ToText(Date.From(_),"dd/MM/yyyy") , type text}}) in #"Extracted Date"
- AnonymousNot applicable
let
Source = let StandardDate = (dateColumn as text,DateSchema as text) =>
letMyDelimiter = Text.Range(DateSchema,Text.PositionOfAny(DateSchema,{"/","-",".","\","_"}),1),
DateList = Splitter.SplitTextByDelimiter(MyDelimiter, QuoteStyle.None)(dateColumn),
SchemaList = Splitter.SplitTextByDelimiter(MyDelimiter, QuoteStyle.None)(DateSchema),
TableDate = Table.FromColumns({DateList,SchemaList}),
myDay = "0" & Text.From(Table.SelectRows(TableDate,each Text.Upper(Text.Range([Column2],0,1)) = "D" )[Column1]{0}),
myDD = Text.Range(myDay,Text.Length(myDay)-2,2),
MyMonth= "0" & Text.From(Table.SelectRows(TableDate,each Text.Upper(Text.Range([Column2],0,1)) = "M" )[Column1]{0}),
myMM = Text.Range(MyMonth,Text.Length(MyMonth)-2,2),
myYear= "20" & Text.From(Table.SelectRows(TableDate,each Text.Upper(Text.Range([Column2],0,1)) = "Y" )[Column1]{0}),
myYYYY = Text.Range(myYear,Text.Length(myYear)-4,4),
DateByParts = myYYYY & "-" & myMM & "-" & myDD,
DateCleaned = Date.FromText(DateByParts)
in DateCleaned
in StandardDate
in
Source - TommiBerlinNew Member
My goal is to get the data for today (so whenever we update the datasource. As the combination of date & text in the web.Contens() is not possible, we had to convert to it to text in an "yyyy-MM-dd".
Solved it like that.
= Json.Document(Web.Contents("https://api.xxxx/client?json=1&from=" & Date.ToText(Date.From(DateTime.LocalNow()),"yyyy-MM-dd") & "&to=" & Date.ToText(Date.From(DateTime.LocalNow()),"yyyy-MM-dd") &"T23:59:59Z"))