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## Cartesian Product of String Lists in M

Hello Everyone,

I'm looking to create a cartesian product of two lists of strings through a function in M. Imagine I have lists {"a","b","c"} and {"1","2","3"} and I want to create a list of lists such that the cartesian product is as follows {{"a1","b1","c1"},{"a2","b2","c2"},{"a3","b3","c3"}}.

How could I approach this?

I've considered using a List.Generate but can't seem to get the right arguments that don't return an error. I was also looking at using List.Transform but again couldn't get it to work.

Any help is appreciated.

Thanks!

2 ACCEPTED SOLUTIONS
Super User

You may use this

``````let
list1 = {"a", "b", "c", "d"},
list2 = {1, 2, 3}
in
List.Split(List.TransformMany(list2, (x)=>list1, (x,y)=> y & Text.From(x)), List.Count(list1))``````
Community Support

Hi @lmgibs04 ,

And you can also try this:

``````let
List1 = {"a", "b", "c"},
List2 = {"1", "2", "3"},
Product = List.Transform(List2, each let currentItem = _ in List.Transform(List1, each _ & currentItem)),
Result = List.Zip(Product),
#"Converted to Table" = Table.FromList(Result, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
#"Extracted Values" = Table.TransformColumns(#"Converted to Table", {"Column1", each Text.Combine(List.Transform(_, Text.From), "#(tab)"), type text}),
#"Split Column by Delimiter" = Table.SplitColumn(#"Extracted Values", "Column1", Splitter.SplitTextByDelimiter("#(tab)", QuoteStyle.Csv), {"Column1.1", "Column1.2", "Column1.3"}),
#"Changed Type" = Table.TransformColumnTypes(#"Split Column by Delimiter",{{"Column1.1", type text}, {"Column1.2", type text}, {"Column1.3", type text}})
in
#"Changed Type"``````

Just put all of this M function into Advanced Editor, and the final output is as below:

Best Regards,
Dino Tao
If this post helps, then please consider Accept both of our answers as the solution to help the other members find it more quickly.

2 REPLIES 2
Community Support

Hi @lmgibs04 ,

And you can also try this:

``````let
List1 = {"a", "b", "c"},
List2 = {"1", "2", "3"},
Product = List.Transform(List2, each let currentItem = _ in List.Transform(List1, each _ & currentItem)),
Result = List.Zip(Product),
#"Converted to Table" = Table.FromList(Result, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
#"Extracted Values" = Table.TransformColumns(#"Converted to Table", {"Column1", each Text.Combine(List.Transform(_, Text.From), "#(tab)"), type text}),
#"Split Column by Delimiter" = Table.SplitColumn(#"Extracted Values", "Column1", Splitter.SplitTextByDelimiter("#(tab)", QuoteStyle.Csv), {"Column1.1", "Column1.2", "Column1.3"}),
#"Changed Type" = Table.TransformColumnTypes(#"Split Column by Delimiter",{{"Column1.1", type text}, {"Column1.2", type text}, {"Column1.3", type text}})
in
#"Changed Type"``````

Just put all of this M function into Advanced Editor, and the final output is as below:

Best Regards,
Dino Tao
If this post helps, then please consider Accept both of our answers as the solution to help the other members find it more quickly.

Super User

You may use this

``````let
list1 = {"a", "b", "c", "d"},
list2 = {1, 2, 3}
in
List.Split(List.TransformMany(list2, (x)=>list1, (x,y)=> y & Text.From(x)), List.Count(list1))``````

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