Forum Discussion
Bulk Renaming Columns after Splitting by Delimiter
- 4 years ago
You can use this where #"Split Column by Delimiter" is last step and it will generate names like "ID","Permit Ref","EndDate", "ID1","Permit Ref1","EndDate1", "ID2","Permit Ref2","EndDate2" and so on. It is not dependent upon how many columns do you have
= Table.TransformColumnNames(#"Split Column by Delimiter",(x)=> if Text.Start(x,5)="data." then {"ID","Permit Ref","EndDate"}{Number.Mod(Number.From(Text.AfterDelimiter(x,"."))-1,3)} else x)See the working here - Open a blank query - Home - Advanced Editor - Remove everything from there and paste the below code to test (later on when you use the query on your dataset, you will have to change the source appropriately. If you have columns other than these, then delete Changed type step and do a Changed type for complete table from UI again)
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("DY6xEcMwDMR2cY1CzycpaRafi+TiBbx/ER8KlMB5Hr/7OTju5+X1hy8mKZrJYqOBhAIZJSrUaKKFNjEIEUGYSKKIJiaxiI0HFg5snLhw44kX3uQgRQb5FpMssslJLnJTgxIVlKl3qKimJrWoTQ9adNCm87iuPw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ColA = _t, ColB = _t, data = _t]), #"Split Column by Delimiter" = Table.SplitColumn(Source, "data", Splitter.SplitTextByDelimiter(",", QuoteStyle.Csv), {"data.1", "data.2", "data.3", "data.4", "data.5", "data.6", "data.7", "data.8", "data.9", "data.10", "data.11", "data.12", "data.13", "data.14", "data.15", "data.16", "data.17", "data.18", "data.19", "data.20", "data.21", "data.22", "data.23", "data.24", "data.25", "data.26", "data.27", "data.28", "data.29", "data.30", "data.31", "data.32", "data.33", "data.34", "data.35", "data.36", "data.37", "data.38", "data.39", "data.40", "data.41", "data.42", "data.43", "data.44", "data.45", "data.46", "data.47", "data.48", "data.49", "data.50", "data.51", "data.52", "data.53", "data.54", "data.55", "data.56", "data.57", "data.58", "data.59", "data.60", "data.61", "data.62", "data.63", "data.64"}), Custom1 = Table.TransformColumnNames(#"Split Column by Delimiter",(x)=> if Text.Start(x,5)="data." then {"ID","Permit Ref","EndDate"}{Number.Mod(Number.From(Text.AfterDelimiter(x,"."))-1,3)} else x) in Custom1
Hello - in this solution you input the number of columns that should be in each set (3), the script calculates the number of sets that exist in the table, renames those columns and does not rename any extra columns. A sample file is attached.
SCRIPT
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("DY4JEcQwDAO5HILIlpwES6dMFvwVwD7P8xNFY8KwOVy0kFChRkZBgzY66FKL+piimjIVaqhNHerSixb9KZs2HXroTR/64oWFC39F4+DBGx98ySIiRZp8QyFDNjnkMosRU0wz/r3vHw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"data.1|data.2|data.3|data.4|data.5|data.6|data.7|data.8|data.9|data.10|data.11|data.12|data.13|data.14|data.15|data.16|data.17|data.18|data.19|data.20|data.21|data.22|data.23|data.24|data.25|data.26|data.27|data.28|data.29|data.30|data.31|data.32|data.33|data.34|data.35|data.36|data.37|data.38|data.39|data.40|data.41|data.42|data.43|data.44|data.45|data.46|data.47|data.48|data.49|data.50|data.51|data.52|data.53|data.54|data.55|data.56|data.57|data.58|data.59|data.60|data.61|data.62|data.63|data.64" = _t]),
SplitCol = Table.SplitColumn(Source, Table.ColumnNames(Source){0}, Splitter.SplitTextByDelimiter("|", QuoteStyle.Csv), Text.Split(Table.ColumnNames(Source){0},"|")),
OldNames =Table.ColumnNames( SplitCol ),
NumberInEachSet = 3,
NumberOfSets = Number.IntegerDivide(List.Count(Table.ColumnNames( SplitCol )),NumberInEachSet),
NewNames = List.Transform(List.Combine(List.Transform({0..NumberOfSets}, each {"ID("&Text.From(_)&")", "Permit Ref("&Text.From(_)&")", "EndDate("&Text.From(_)&")"})), each Text.Replace(_, "(0)", "") ),
RenameColumns = Table.RenameColumns( SplitCol, List.Range(List.Zip({OldNames,NewNames}),0,NumberInEachSet*NumberOfSets))
in
RenameColumns
BEFORE
RESULT