Forum Discussion

yogevz's avatar
yogevz
Helper II
7 years ago
Solved

running diff after sum

hi

i have to tables, upon them i am creating list which aggregate the measure in a list.

i want to create running diff on rows.

attach picture.

Need Help
  • v-lili6-msft's avatar
    v-lili6-msft
    7 years ago

    hi, yogevz

    After my test, you could use this formula to create a measure as below:

    Measure = CALCULATE([Count_student measure])- CALCULATE([Count_student measure],FILTER(ALL(Sheet1),Sheet1[Foreign]=MAX(Sheet1[Foreign])-1))

    Count_student measure is a measure which count students.

     

    Result:

    201811304

     

    Best Regards,

    Lin

     

     

5 Replies

  • themistoklis's avatar
    themistoklis
    Community Champion
    7 years ago

    yogevz

     

    Please try the following DAX formula:

    DIFFERENCE = 
var previous = CALCULATE(FIRSTNONBLANK(Table[count_student];Table[count_student]);FILTER(Table;Table[ForeignYear]=EARLIER(Table[ForeignYear]) )) 
return IF(ISBLANK(previous);0; Table[count_student]-previous)
  • themistoklis's avatar
    themistoklis
    Community Champion
    7 years ago

    Use this one instead. In a new column and not measure

     

    DIFF = 
var previous = CALCULATE(FIRSTNONBLANK(Sheet1[count_student], Sheet1[count_student]), FILTER(Sheet1, Sheet1[ForeignYear]=EARLIER(Sheet1[ForeignYear] ) -1))
return IF(ISBLANK(previous),0, Sheet1[count_student]-previous)

    IMage below:

     

     

    • yogevz's avatar
      yogevz
      Helper II
      7 years ago

      i can't....

      the count_student is a measure which count students...

      so the column phrase can't see this measure.

      this is the problem....

      • themistoklis's avatar
        themistoklis
        Community Champion
        7 years ago

        You can try this formula:

        New_Diff = SUM(Sheet1[count_student]) - IF(MAX(Sheet1[ForeignYear])=1, SUM(Sheet1[count_student]), LOOKUPVALUE(Sheet1[count_student], Sheet1[ForeignYear], MAX(Sheet1[ForeignYear])-1))