Forum Discussion
remove filter in row context
Hi,
I am using a measure on Card and table visuals. The measure is giving correct value when using it on the card visual but due to row context, it divide the values when placing this measure on table visual along with some fields.
I need aggregated values on table visual also irrespective of row values of fields used on the table.
Thanks
Hi,
Not 100% sure of what you expect but if I get it right using ALL instead of ALLEXCEPT should do the trick :
Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[Stage]))
Return
PeerCountEven if you want to get rid of all filters on table pfs :Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs'))
Return
PeerCountHope it helps
4 Replies
- AilleryOMemorable Member
Hi,
Sorry my bad, should be :
Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[CNumber]))
Return
PeerCountAssuming CNumber is the peer number you need to remove to aggregate.
Or :
Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs',[Stage]))
Return
PeerCountCould be another solution, to keep filters on Stage (assuming stage is the column with High, Low, Verbal).
Hope it helps
- AnonymousNot applicable
Hi Anonymous ,
Please try this measure.
Count = VAR CNo = SELECTEDVALUE ( 'cfs'[CNumber], BLANK () ) VAR PCount = CALCULATE ( DISTINCTCOUNT ( 'pfs'[CNumber] ), FILTER ( ALL ( 'pfs' ), 'pfs'[CNumber] <> CNo ) ) VAR PeerCount = CALCULATE ( PCount, ALL ( 'pfs'[CNumber] ), ALLSELECTED ( 'cfs'[CNumber] ) ) RETURN PeerCountIf this doesn't work, please consider providing a sample of the data without privacy.
Best Regards,
Gao
Community Support TeamIf there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
How to get your questions answered quickly -- How to provide sample data
- AilleryOMemorable Member
Hi,
Not 100% sure of what you expect but if I get it right using ALL instead of ALLEXCEPT should do the trick :
Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[Stage]))
Return
PeerCountEven if you want to get rid of all filters on table pfs :Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs'))
Return
PeerCountHope it helps- AnonymousNot applicable
AilleryO , I have been tried with All also but it doesn't remove the filter and ALLEXCEPT need minimum 2 argument.
ALLEXCEPT('pfs')
I need aggregated values in each row like this: