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Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

remove filter in row context

Hi,

I am using a measure on Card and table visuals. The measure is giving correct value when using it on the card visual but due to row context, it divide the values when placing this measure on table visual along with some fields. 

I need aggregated values on table visual also irrespective of row values of fields used on the table.

 

Count =
var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
var PCount = CALCULATE( DISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs',[Stage]))
Return
           PeerCount
 
when placing this measure "Count" with the field "Stage" on a table visual, it divides the values in row context while it should be 5 for all values of Stage.
 

 

Thanks


 

  • Hi,

     

    Not 100% sure of what you expect but if I get it right using ALL instead of ALLEXCEPT should do the trick :

    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[Stage]))
    Return
               PeerCount
     
    Even if you want to get rid of all filters on table pfs :
     
    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs'))
    Return
               PeerCount
     
    Hope it helps
     

4 Replies

  • AilleryO's avatar
    AilleryO
    Memorable Member

    Hi,

     

    Sorry my bad, should be :

    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[CNumber]))
    Return
          PeerCount

     Assuming CNumber is the peer number you need to remove to aggregate.

    Or :

    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs',[Stage]))
    Return
          PeerCount

     

    Could be another solution, to keep filters on Stage (assuming stage is the column with High, Low, Verbal).

    Hope it helps

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi Anonymous ,

     

    Please try this measure.

    Count = 
    VAR CNo =
        SELECTEDVALUE ( 'cfs'[CNumber], BLANK () )
    VAR PCount =
        CALCULATE (
            DISTINCTCOUNT ( 'pfs'[CNumber] ),
            FILTER ( ALL ( 'pfs' ), 'pfs'[CNumber] <> CNo )
        )
    VAR PeerCount =
        CALCULATE ( PCount, ALL ( 'pfs'[CNumber] ), ALLSELECTED ( 'cfs'[CNumber] ) )
    RETURN
        PeerCount

    If this doesn't work, please consider providing a sample of the data without privacy.

     

    Best Regards,
    Gao

    Community Support Team

     

    If there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!

    How to get your questions answered quickly -- How to provide sample data

  • AilleryO's avatar
    AilleryO
    Memorable Member

    Hi,

     

    Not 100% sure of what you expect but if I get it right using ALL instead of ALLEXCEPT should do the trick :

    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALL('pfs',[Stage]))
    Return
               PeerCount
     
    Even if you want to get rid of all filters on table pfs :
     
    Count =
    var CNo = SELECTEDVALUE('cfs'[CNumber],BLANK())
    var PCount = CALCULATEDISTINCTCOUNT ('pfs'[CNumber]) , 'pfs'[CNumber] <> CNo, ALLEXCEPT('pfs'))
    Return
               PeerCount
     
    Hope it helps
     
    • Anonymous's avatar
      Anonymous
      Not applicable

      AilleryO , I have been tried with All also but it doesn't remove the filter and ALLEXCEPT need minimum 2 argument.

      ALLEXCEPT('pfs')

      I need aggregated values in each row like this: