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Anonymous
Not applicable

issues starting with serial at didderent loaction as 1 issue

hi
i have  a column Issues using which i have to show all the issues in a graph
i want to consider all the issues starting with serial at didderent loaction as 1 issue 

greeshma_0-1623233612194.png

 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi  @Anonymous ,

Here are the steps you can follow:

1. Create calculated column.

new =
IF(CONTAINSSTRING('Table'[column],"Serial at different location"),"Serial at different loaction",'Table'[column])

2. Create measure.

count = COUNTAX(FILTER(ALL('Table'),'Table'[new]=MAX('Table'[new])),'Table'[new])

3. Result:

v-yangliu-msft_0-1623396558920.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi  @Anonymous ,

Here are the steps you can follow:

1. Create calculated column.

new =
IF(CONTAINSSTRING('Table'[column],"Serial at different location"),"Serial at different loaction",'Table'[column])

2. Create measure.

count = COUNTAX(FILTER(ALL('Table'),'Table'[new]=MAX('Table'[new])),'Table'[new])

3. Result:

v-yangliu-msft_0-1623396558920.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

amitchandak
Super User
Super User

@Anonymous , second part is not clear ,

 

Create a measure

calculate(countrows(Table), filter(table, left([column],6) ="Serial" && Search("Location",[Column],,0) >0))

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Anonymous
Not applicable

hi amit

i have used your measure but it is still showing the division of serial at different location.
i just want to show all the serial at different location as one

greeshma_0-1623237826839.png

 

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