Starting December 3, join live sessions with database experts and the Microsoft product team to learn just how easy it is to get started
Learn moreGet certified in Microsoft Fabric—for free! For a limited time, get a free DP-600 exam voucher to use by the end of 2024. Register now
Hello! I have a measure X, and also a calculated column N.
N X
1 0.9
2 0.8
3 0.7
4 0.8
.....
I need to calculate a measure Y, so that Y(n)=X(n)+Y(n-1)
so that
N X Y
1 0.9 0.9
2 0.8 1.7
3 0.7 2.4
.....
In this case , N is a calculated column , X is a measure I calculated, how to calculate Y? Thank you in advance!
Solved! Go to Solution.
Hi DuoHappy,
I did it with a date tables as an example
in my case N=date of date table (column)
X= a Measure which counts the days
Y = the measure which calculates the running total based on the date
Y =
CALCULATE(
[X (Count of Days)],
FILTER(ALL('Dim Date'),
'Dim Date'[Date] <= MAX('Dim Date'[Date])
)
)
Did you try this?
Y =
CALCULATE(
[X],
FILTER(ALL('Table where N is stored'),
'Table where N is stored'[N] <= MAX('Table where N is stored'[N])
)
)
Hi, @Anonymous ;
You could try it.
Measure = SUMX(FILTER(ALL('Table'),[No]<=MAX('Table'[No])),[X])
The final show:
If the above one can't help you get the desired result, please provide a simplified pbix file. You can refer the following link to upload the file to the community. Thank you.
How to upload PBI in Community
Best Regards,
Community Support Team _ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, @Anonymous ;
You could try it.
Measure = SUMX(FILTER(ALL('Table'),[No]<=MAX('Table'[No])),[X])
The final show:
If the above one can't help you get the desired result, please provide a simplified pbix file. You can refer the following link to upload the file to the community. Thank you.
How to upload PBI in Community
Best Regards,
Community Support Team _ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi DuoHappy,
I did it with a date tables as an example
in my case N=date of date table (column)
X= a Measure which counts the days
Y = the measure which calculates the running total based on the date
Y =
CALCULATE(
[X (Count of Days)],
FILTER(ALL('Dim Date'),
'Dim Date'[Date] <= MAX('Dim Date'[Date])
)
)
In your case, NO. is from dim date, but in my case No. is a calculated column from Fact table, which has multiple values.
Hi DuoHappy,
It doesn't matter. It also works with duplicates thanks to the MAX() function.
Best regards
Michael
Did you try this?
Y =
CALCULATE(
[X],
FILTER(ALL('Table where N is stored'),
'Table where N is stored'[N] <= MAX('Table where N is stored'[N])
)
)
sorry, it is not working in my case
ah okay,
is there a multiplication in your x measure going? If yes you have to sorround my solutuion with a SUMX
Y =
SUMX(
VALUES('Table of N'[N]),
CALCULATE(
[X],
FILTER(ALL('Table where N is stored'),
'Table where N is stored'[N] <= MAX('Table where N is stored'[N])
)
)
)
Hello! I thought I can not using your suggestion to get the right answer. This might because in my calculation of X, I also used all function in the formula. and now Y if using all function again, which caused problem so that this value is not correct
Hello! Thanks ! I am thinking Y=
CALCULATE(
sum([X]),
FILTER(ALL('Table where N is stored'),
'Table where N is stored'[N] <= MAX('Table where N is stored'[N])
)
)
but it is wrong.
Hi,
I am not sure if I understood your question correctly, but please check the below picture and the attached pbix file.
Expected result measure: =
[Sales measure:]
+ CALCULATE ( [Sales measure:], Data[Index CC] <= MAX ( Data[Index CC] ) - 1 )
If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.
Hi, using you syntax can not get the value you showed, please see. Could you please give more guidance?
Hi,
Please share your sample pbix file's link here, and then I can try to look into it.
Thanks.
If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.
@Anonymous
in the above case is actually a multiplication of column wiht measure is that right?
then in the data view along with N , add another column with X = X measure , it gives you the value of measure as a column in the table
Then you can use sumx(table, n*x) will give youthe value as requried!
Proud to be a Super User!
Starting December 3, join live sessions with database experts and the Fabric product team to learn just how easy it is to get started.
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early Bird pricing ends December 9th.
User | Count |
---|---|
94 | |
87 | |
82 | |
71 | |
49 |
User | Count |
---|---|
143 | |
124 | |
107 | |
60 | |
55 |