find 2 latest wages by employee and calculate increase amount

[Anonymous]

Hi, I have a really tricky calculation for me that I can't resolve. I have a wage table where is all wages of employees. I need to calculate how much have the wage increased. There can be multiple wage increases/employee and it has to be calculated from the two latest agreement.

For example Employee.Id 1: Calculate(sum(monthlywage1-monthlywage2) where employee.id = 1 and monthlywage1=latestwage and monthlywage2 =secondlatest wage.

Id	Employee.Id	Startdate	MonthlyWage
1	1	01.01.2018	1000
2	2	10.01.2019	3000
3	1	01.01.2019	1500
4	2	05.11.2020	3200
5	1	01.01.2021	2000
6	3	28.10.2020	1500
7	3	01.09.2021	1600

[v-stephen-msft · Accepted solution]

Hi @Anonymous ,

You can create two calculated columns

rank =
RANKX (
    FILTER ( 'Table', [Employee.Id] = EARLIER ( 'Table'[Employee.Id] ) ),
    [Startdate],
    ,
    ASC,
    DENSE
)

increase amount =
VAR _amount =
    CALCULATE (
        SUM ( 'Table'[MonthlyWage] ),
        FILTER (
            'Table',
            [Employee.Id] = EARLIER ( 'Table'[Employee.Id] )
                && [rank]
                    = EARLIER ( 'Table'[rank] ) - 1
        )
    )
RETURN
    IF ( ISBLANK ( _amount ), 0, [MonthlyWage] - _amount )

Best Regards,

Stephen Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Anonymous]

Hi,

Great this works like a charm :)! Thank you very much!

[amitchandak]

@Anonymous ,

Meausre =
var _max = calculate(Max(Table[Startdate]), allexcept(Table, Table[Employee.ID]))
var _max2 = calculate(MaxX(Filter(Table, Table[Startdate]<_max),Table[Startdate] ), allexcept(Table, Table[Employee.ID]))
return
calculate(sumX(values(Table[employee.id]) , calculate(sum(Table[MonthlyWage]), filter(Table, Table[Startdate]=_max)) -calculate(sum(Table[MonthlyWage]), filter(Table, Table[Startdate]=_max1))))

[Anonymous]

Hi @amitchandak for some reason the calculation returns incorrect result. for example previous wage has been 1337 and new wage is 3000. The result should be 1663(the difference between current and previous wage) but calculation returns -1337