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skills29
Frequent Visitor

filtered and not filtered values in the same table when filtered

Hello guys, could someone help me. I have a matrix which contains NameProject in rows, Month/Year in Columns and a column name Status from f_status_projects table as shown below:

skills29_1-1687455612273.png

 

When i use a slicer visual to filter this matrix by status, for example Suspended:

skills29_2-1687455636823.png

However, I want it to keep appearing the name of the other status that are not suspended when one of the columns has a suspended status, and when there is no suspended status, it doesn't appear as it already does. So, i want the matrix be like this when filter Suspended projects:

skills29_3-1687455853317.png

 

Could someone help please?

 

1 ACCEPTED SOLUTION
v-yangliu-msft
Community Support
Community Support

Hi  @skills29 ,

 

Here are the steps you can follow:

1. Create calculated table.

Table 2 =
DISTINCT('Table'[Status])

vyangliumsft_0-1687763478119.png

2. Create measure.

Measure =
var _select=SELECTCOLUMNS('Table 2',"1",[Status])
var _proj=
SELECTCOLUMNS(
    FILTER(ALL('Table'),'Table'[Status] in _select),"1",[ProjectName])
return
IF(
    MAX('Table'[ProjectName]) in _proj ,MAX('Table'[Status]),BLANK())

3. Result:

vyangliumsft_1-1687763478128.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

2 REPLIES 2
v-yangliu-msft
Community Support
Community Support

Hi  @skills29 ,

 

Here are the steps you can follow:

1. Create calculated table.

Table 2 =
DISTINCT('Table'[Status])

vyangliumsft_0-1687763478119.png

2. Create measure.

Measure =
var _select=SELECTCOLUMNS('Table 2',"1",[Status])
var _proj=
SELECTCOLUMNS(
    FILTER(ALL('Table'),'Table'[Status] in _select),"1",[ProjectName])
return
IF(
    MAX('Table'[ProjectName]) in _proj ,MAX('Table'[Status]),BLANK())

3. Result:

vyangliumsft_1-1687763478128.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

Thank you so much, it has worked!

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