Forum Discussion
different dax query for each row
I have two tables
table 1
id a b c d (columns)
1 0 1 1 1 (rows)
2 1 0 1 0
table 2
feature adoption frequency (columns)
a
b
c
d
Now i want to fill adoption column in table 2. This column will have count of all the "1" from table 1. I need to match column value (feature) from table 2 and column (a) from table 1.
eg adoption for feature 'a' will count of all the rows from column 'a' in table 1 where row value=1.
How can I implement this? All the columns in both the tables are calculated columns.
Hi Anonymous,
I try to reproduce yourscenario and get expected result using the following steps.
1. Right click Table1 -> Edit Query, like the screenshot.
2. Select a,b,c,d column->click Unpivot columns->Close&Apply. You will get the table like the second screenshot below.
3. Create a relationship between Table1 and Table2. More details about creating and management relationship, please review this article.
4. Create a calculated column using the formula, you will get the desired result.adoption = CALCULATE(COUNT(Table1[Value]),Table1[Value]=1)
If you have other issues, don't hesitate to let me know.Best Regards,
Angelia
2 Replies
That's pretty nasty. Off the top of my head, maybe a custom column in table 2, something like:
IF([Feature] = "a",SUM('table 1'[a]),IF([Feature] = "b",SUM('table 1[b],...Probably cleaner with a SWITCH statement.
Hi Anonymous,
I try to reproduce yourscenario and get expected result using the following steps.
1. Right click Table1 -> Edit Query, like the screenshot.
2. Select a,b,c,d column->click Unpivot columns->Close&Apply. You will get the table like the second screenshot below.
3. Create a relationship between Table1 and Table2. More details about creating and management relationship, please review this article.
4. Create a calculated column using the formula, you will get the desired result.adoption = CALCULATE(COUNT(Table1[Value]),Table1[Value]=1)
If you have other issues, don't hesitate to let me know.Best Regards,
Angelia
