Forum Discussion
count ifs
I am trying to count the number of floors per building per facility. I am using two measures to get this but it is not working
Any help would be greatly appreciated.
Anonymous This is because you have [Floor] still in the table. A couple of things you can do, either use a matrix visual instead to get the subtotals;
[Count of Floors] in Values
[Facility] in Rows
[Building] in Rows
[Floor] in Rows
Expand down to all levels using the double connected arrows (looks like a fork kind of) at top of matrix.
or update your measure:
Count of All Floors = CALCULATE(COUNTA('public facilities'[name]) , ALL('public facilities'[floor]))
4 Replies
Anonymous ,
Have you tried DISTINCTCOUNT('public facilities'[name]) ?
Anonymous The countifs in DAX comes down to how you use it, if you want to count number of floors, simply create a measure:
Count of Floors = COUNTA('public facilities'[name])
Then put this in a table or matrix visual. If using a matrix, put:
[Count of Floors] in Values
[Facility] in Rows
[Building] in Rows
If using a table, just put them in this order:
[Facility]
[Building]
[Count of Floors]
If you want distinct count, use camargos88 formula.
You can also use the COUNTROWS formula you have already created if you want to include blank values in your count.
Hope that makes sense?
AllisonKennedy I created the measure count of floor ( COUNTA('public facilities'[name]) ). I am still not geting the floors to total up. If you look at the first one there is 2 garages with 6 floors each. I am needing it to be North Garage 6 floors and West Garage 6 Floors.
Anonymous This is because you have [Floor] still in the table. A couple of things you can do, either use a matrix visual instead to get the subtotals;
[Count of Floors] in Values
[Facility] in Rows
[Building] in Rows
[Floor] in Rows
Expand down to all levels using the double connected arrows (looks like a fork kind of) at top of matrix.
or update your measure:
Count of All Floors = CALCULATE(COUNTA('public facilities'[name]) , ALL('public facilities'[floor]))
