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Anonymous's avatar
Anonymous
Not applicable
2 years ago
Solved

clustered column chart with category

Hello,

I want to represent count based status in my approval status cloumn. Let's say this column have 4 different statuses, I want each status to be represented in the chart.

In power by, I have a column status but when doing a count, I get one bar in the chart representing the total. I have tried creating count by status, count filtered...all got back to 

 

  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi  Anonymous ,

     

    You can try to create a table with a Status column.

    Create a measure, use the Switch() function to determine which state gets the corresponding value, then place [Status] on the X-axis and [Measure] on the Y-axis.

    If it doesn't meet your desired outcome, can you share sample data and sample output in table format? Or a sample pbix after removing sensitive data. We can better understand the problem and help you

     

    Best Regards,

    Liu Yang

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

3 Replies

  • Anonymous what are you using on the x-axis and value well of the visual?

    • Anonymous's avatar
      Anonymous
      Not applicable

      Somtimes explaining the problem is just enough to answer it. I was not using the proper x-axis and went down a rabbit hole trying to write DAX expression for something that was as easy as a drag and drop.

      Problem solved using the "Approval status" in x-axis

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi  Anonymous ,

     

    You can try to create a table with a Status column.

    Create a measure, use the Switch() function to determine which state gets the corresponding value, then place [Status] on the X-axis and [Measure] on the Y-axis.

    If it doesn't meet your desired outcome, can you share sample data and sample output in table format? Or a sample pbix after removing sensitive data. We can better understand the problem and help you

     

    Best Regards,

    Liu Yang

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly