Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Next up in the FabCon + SQLCon recap series: The roadmap for Microsoft SQL and Maximizing Developer experiences in Fabric. All sessions are available on-demand after the live show. Register now

Reply
reinaldoc_
Regular Visitor

YEARFRAC bug?

Its normal or is a bug with YEARFRAC?

 

 

 

Table = 
  VAR _T =
    ADDCOLUMNS(
      GENERATESERIES (2010, 2022, 1),
      "Today in the past", DATE([Value], MONTH(TODAY()), DAY(TODAY()))
    )
  RETURN
    ADDCOLUMNS(
      _T,
      "YEARFRAC", YEARFRAC([Today in the past], TODAY(), 1)
    )

 

 

image.png

2 ACCEPTED SOLUTIONS
OwenAuger
Super User
Super User

Hi @reinaldoc_ 

I believe this is the intended behaviour of YEARFRAC, and you will get the same result using Excel's YEARFRAC function.

 

Did you expect integers to be returned in all cases? You could use Basis argument = 0 as one option.

 

With the Basis argument set to 1, the calculation is

 

YEARFRAC = (EndDate - StartDate) / ( Simple average of days per complete calendar year for the years spanning StartDate to EndDate-1 )

 

For 2020, the calculation would be

YEARFRAC = ( DATE(2023,11,11) - DATE(2020,11,11) ) / ( (366+365+365+365)/4 ) = 2.998

 

You can verify this by adding a manual calculation to the query like this:

https://dax.do/x3vEBqrkCHEjkR/

 

EVALUATE
VAR _T =
    ADDCOLUMNS (
        GENERATESERIES ( 2010, 2022, 1 ),
        "Today in the past", DATE ( [Value], MONTH ( TODAY () ), DAY ( TODAY () ) )
    )
RETURN
    ADDCOLUMNS (
        _T,
        "YEARFRAC", YEARFRAC ( [Today in the past], TODAY (), 1 ),
        "YEARFRAC Manual",
            VAR DateRange =
                ADDCOLUMNS (
                    CALENDAR ( [Today in the past], TODAY () - 1 ),
                    "@Year", YEAR ( [Date] )
                )
            VAR NumDays =
                TODAY () - [Today in the past]
            VAR DaysPerYear =
                ADDCOLUMNS (
                    GROUPBY ( DateRange, [@Year] ),
                    "@DaysPerYear",
                        (
                            DATE ( [@Year] + 1, 1, 1 )
                                - DATE ( [@Year], 1, 1 )
                        )
                )
            VAR DaysPerYearSimpleAverage =
                AVERAGEX ( DaysPerYear, [@DaysPerYear] )
            RETURN
                DIVIDE ( NumDays, DaysPerYearSimpleAverage )
    )

Regards


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
LinkedIn

View solution in original post

OwenAuger
Super User
Super User

That appears to be deceptive formatting. Turn off Auto format to see the values:

OwenAuger_0-1699768673979.png

 


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
LinkedIn

View solution in original post

3 REPLIES 3
OwenAuger
Super User
Super User

That appears to be deceptive formatting. Turn off Auto format to see the values:

OwenAuger_0-1699768673979.png

 


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
LinkedIn
OwenAuger
Super User
Super User

Hi @reinaldoc_ 

I believe this is the intended behaviour of YEARFRAC, and you will get the same result using Excel's YEARFRAC function.

 

Did you expect integers to be returned in all cases? You could use Basis argument = 0 as one option.

 

With the Basis argument set to 1, the calculation is

 

YEARFRAC = (EndDate - StartDate) / ( Simple average of days per complete calendar year for the years spanning StartDate to EndDate-1 )

 

For 2020, the calculation would be

YEARFRAC = ( DATE(2023,11,11) - DATE(2020,11,11) ) / ( (366+365+365+365)/4 ) = 2.998

 

You can verify this by adding a manual calculation to the query like this:

https://dax.do/x3vEBqrkCHEjkR/

 

EVALUATE
VAR _T =
    ADDCOLUMNS (
        GENERATESERIES ( 2010, 2022, 1 ),
        "Today in the past", DATE ( [Value], MONTH ( TODAY () ), DAY ( TODAY () ) )
    )
RETURN
    ADDCOLUMNS (
        _T,
        "YEARFRAC", YEARFRAC ( [Today in the past], TODAY (), 1 ),
        "YEARFRAC Manual",
            VAR DateRange =
                ADDCOLUMNS (
                    CALENDAR ( [Today in the past], TODAY () - 1 ),
                    "@Year", YEAR ( [Date] )
                )
            VAR NumDays =
                TODAY () - [Today in the past]
            VAR DaysPerYear =
                ADDCOLUMNS (
                    GROUPBY ( DateRange, [@Year] ),
                    "@DaysPerYear",
                        (
                            DATE ( [@Year] + 1, 1, 1 )
                                - DATE ( [@Year], 1, 1 )
                        )
                )
            VAR DaysPerYearSimpleAverage =
                AVERAGEX ( DaysPerYear, [@DaysPerYear] )
            RETURN
                DIVIDE ( NumDays, DaysPerYearSimpleAverage )
    )

Regards


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
LinkedIn

Thanks, but the code that I submit results in integers on dax.do, can you verify?

Helpful resources

Announcements
New to Fabric survey Carousel

New to Fabric Survey

If you have recently started exploring Fabric, we'd love to hear how it's going. Your feedback can help with product improvements.

Power BI DataViz World Championships carousel

Power BI DataViz World Championships - June 2026

A new Power BI DataViz World Championship is coming this June! Don't miss out on submitting your entry.

Join our Fabric User Panel

Join our Fabric User Panel

Share feedback directly with Fabric product managers, participate in targeted research studies and influence the Fabric roadmap.

March Power BI Update Carousel

Power BI Community Update - March 2026

Check out the March 2026 Power BI update to learn about new features.