Forum Discussion

Oomsen's avatar
Oomsen
Helper III
7 years ago
Solved

Working hours until today

With the measure below i calculate the workable hours:

Werkuren = IF('Medewerker uren'[Dag]=2;7,6;0)&IF('Medewerker uren'[Dag]=3;7,6;0)&IF('Medewerker uren'[Dag]=4;7,6;0)&IF('Medewerker uren'[Dag]=5;7,6;0)&IF('Medewerker uren'[Dag]=6;7,6;0)
 
I would like to adjust the measure or create a new one to exclude al hours after today.
  • Oomsen's avatar
    Oomsen
    7 years ago

    v-diye-msft 

    It didn't solve the problem. 

    But with some try and error i found the solution:

    I changed my measure to :
    Werkuren tot vandaag = CALCULATE(SUM('Medewerker uren'[Werkuren]);FILTER(Dimdate;Dimdate[Datum]<=TODAY()))
     
     

4 Replies

  • v-diye-msft's avatar
    v-diye-msft
    Community Support

    Hi Oomsen 

     

    Could you please specify the meaning of your formula? I can barely understand it. It’s preferred to share us your detailed data (upload your pbix to Onedrive and share links here) but kindly masking your confidential info.

     

    We’d like to provide further support once we got it.

     

    Best regards,

    Dina Ye

    • Oomsen's avatar
      Oomsen
      Helper III

      Hi v-diye-msft 

       

      The measure is ment for counting available working hours and compare them with the actuals worked hours of employees. 

      I will translate it to english:

      Working hours = IF('Employee hours'[Day]=2;7,6;0)&IF('Employee hours'[Day]=3;7,6;0)&IF('Employee hours'[Day]=4;7,6;0)&IF('Employee hours'[Day]=5;7,6;0)&IF('Employee hours'[Day]=6;7,6;0)
       
      Our working days contain 7,6 hours. So what i did is count 7,6 if the day is a monday, tuesday, wednesday, thursday or friday. I display this per month and can see what the "workable" hours are per month.
       
      I compare this with the actuals hours and report a % of worked hours witch is nog more then dividing actuals by workable hours.
      But when i do this nowm, i compare actuals (correct) with all workable hours (incorrect). That is why i would like to adjust my measure so that in only count 7,6 hours a day until today.