Forum Discussion
Visual using measures runs slow
- 6 years ago
So the problem with measures that use patterns like IF( <condition>, 1, 0 ) is that they effectively generate a lot of data that does not exist in your data source. If you have sales data and you table a table with Customer, Product and Date you are forcing the engine to calculate a value for every product for every customer on every day.
Since you are only interested in the 1's changing this to IF( <condition>, 1, BLANK() ) should dramatically increase your performance as the tabular engine is very good at skipping blanks.
But possibly an even faster approach is to just do a countrows of your filter condition which will avoid the IF logic entirely
Value of Highlight W =
countrows(
Filter('Table', 'Table'[Material Type]<>"ZOG" && ('Table'[Width] < 0.01 || ISBLANK( 'Table'[Width] )) - 6 years ago
So you cannot divide the FILTER() function (which returns a table with multiple rows and columns) by a count rows. You should not need to change the [% of width] measure at all - the old measure that references [Value of Highlight W] should still work.
Or you could simplify it and reduce it down to the following (note I recommend getting in the habit of using the DIVIDE() function instead of the numeric / operator as it safely handles divide by 0 or divide by blank)
% of width = DIVIDE( [Value of Highlight W] , Countrows( All(zcvrMaterial) ) )
Thanks d_gosbell ,
It now works a little faster compare to previous.
However, I also have a measure which calculates the % of occurence of 1's
I have used this measure base on my previous measure.
Filter('Table', 'Table'[Material Type]<>"ZOG" && ('Table'[Width] < 0.01 || ISBLANK( 'Table'[Width] )/Countrows(FILTER('Table','Table'[Hightlight of Width] (All(zcvrMaterial))))
So you cannot divide the FILTER() function (which returns a table with multiple rows and columns) by a count rows. You should not need to change the [% of width] measure at all - the old measure that references [Value of Highlight W] should still work.
Or you could simplify it and reduce it down to the following (note I recommend getting in the habit of using the DIVIDE() function instead of the numeric / operator as it safely handles divide by 0 or divide by blank)
% of width = DIVIDE( [Value of Highlight W] , Countrows( All(zcvrMaterial) ) )
- Anonymous6 years agoNot applicable
Thanks d_gosbell ,
This has now solved my problem.
I did get the infinite output as my value was getting divide by blank.
I have now used the divide function.
Thanks for all your help!
-Tejaswi