Forum Discussion

Anonymous

Not applicable

5 years ago

Solved

Value difference by Date and categorial variable

Hi all

I want to calculate the difference between values, based on the date as well as another categorial variable.

All that should be displayed in a waterfall diagram (column Expected Result). I attached a screenshot with dummy data and the expectet outcome.

Thanks in advance!

Anonymous
5 years ago
Hi Anonymous ，

Based on your description, you can do some steps as follows.
Create a column to mark month.

Month = MONTH('Diff'[Date])
2. Create a new measure.

Test Value =

var x1=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

var x2=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])-1&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

return

x1-x2

Result:

Hope that's what you were looking for.
Best Regards,
Yuna

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

5 Replies

amitchandak
Super User
5 years ago
Anonymous , Try a new column like

new column =
var _max = maxx(filter(Table, [cat] =earlier([cat]) && [Date] <earlier([Date])),[Date])
return
[value] - maxx(filter(Table, [cat] =earlier([cat]) && [Date] =_max),[value])
- Anonymous
  Not applicable
  5 years ago
  amitchandakThank you very much for your reply!
  Unfortunately I get an error ("syntax for return is incorrect").
  Thanks again 🙂
Anonymous
Not applicable
5 years ago
Hi Anonymous ，

Based on your description, you can do some steps as follows.
Create a column to mark month.

Month = MONTH('Diff'[Date])
2. Create a new measure.

Test Value =

var x1=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

var x2=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])-1&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

return

x1-x2

Result:

Hope that's what you were looking for.
Best Regards,
Yuna

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- Anonymous
  Not applicable
  5 years ago
  Hi, thank you very much for your help!! It worked perfectly 🙂
  Thanks again!
Ashish_Mathur
Super User
5 years ago
Hi,

Try this calculated column formula

=data[value]-lookupvalue(data[value],data[date],calculate(max(data[date]),filter(data,data[cat]=earlier(data[cat])&&data[date]<earlier(data[date]))),data[cat],data[cat])

Hope this helps.