Forum Discussion
Using Variable Instead of Column Reference
- 6 years ago
Hi rawiswarden ,
Sorry for that We cannot find an effective way to add variables with a column and use it the PERCENTILE.INC function.
But we can simplify the formula as following, If you want to create another measure such as yearly, just chang the Dimension_Portstats[MonthlyIncome] to the column in this formula.
Monthly Income (Bin) = VAR __Column = Dimension_Portstats[MonthlyIncome] VAR __25pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.25) VAR __50pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.50) VAR __75pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.75) VAR __25label = "["&min(Dimension_Portstats[MonthlyIncome])&"-"&__25pct&"]" VAR __50label = "("&__25pct&"-"&__50pct&"]" VAR __75label = "("&__50pct&"-"&__75pct&"]" VAR __100label = "("&__75pct&"+]" RETURN SWITCH(TRUE, __Column <= __25pct, __25label, __Column <= __50pct, __50label, __Column <= __75pct, __75label, __100label)If it doesn’t meet your requirement, could you please show the exact expected result based on the table that we have shared?
Best regards,
Hi rawiswarden ,
Sorry for that We cannot find an effective way to add variables with a column and use it the PERCENTILE.INC function.
But we can simplify the formula as following, If you want to create another measure such as yearly, just chang the Dimension_Portstats[MonthlyIncome] to the column in this formula.
Monthly Income (Bin) =
VAR __Column = Dimension_Portstats[MonthlyIncome]
VAR __25pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.25)
VAR __50pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.50)
VAR __75pct = PERCENTILE.INC(Dimension_Portstats[MonthlyIncome], 0.75)
VAR __25label = "["&min(Dimension_Portstats[MonthlyIncome])&"-"&__25pct&"]"
VAR __50label = "("&__25pct&"-"&__50pct&"]"
VAR __75label = "("&__50pct&"-"&__75pct&"]"
VAR __100label = "("&__75pct&"+]"
RETURN
SWITCH(TRUE,
__Column <= __25pct, __25label,
__Column <= __50pct, __50label,
__Column <= __75pct, __75label,
__100label)
If it doesn’t meet your requirement, could you please show the exact expected result based on the table that we have shared?
Best regards,
- rawiswarden6 years agoHelper I
I'd prefer to only have to change the column in one place, but I'll take what I can get!