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Hi ,
I am using user relation function in filter inside calculate function
it is throwing me error saying 'USERELATIONSHIP function can only be used in the CALCULATE function.'
I have created inactive relation between 'instance number ' & 'planned_Number' many to many
I am creating this measure in Routes Table
Solved! Go to Solution.
Hi @jeffrock ,
Please try this measure.
Count = CALCULATE(
DISTINCTCOUNT(DEADLINE[WI_ID]),
USERELATIONSHIP(ROUTES[Assigned_Vehicle], DEADLINE[INSTANCE_NUMBER]),
USERELATIONSHIP(ROUTES[Date2], DEADLINE[DATE_RELEASED]),
USERELATIONSHIP(ROUTES[Date2], DEADLINE[Date_Delivered2]),
FILTER(
ALL(DEADLINE),
max(ROUTES[Assigned_Vehicle]) = max(DEADLINE[INSTANCE_NUMBER]) &&
max(ROUTES[Date2]) > max(DEADLINE[DATE_RELEASED]) &&
max(ROUTES[Date2] )<max( DEADLINE[Date_Delivered2])
)
)
You can refer to the following documents that may be helpful to you:
USERELATIONSHIP function (DAX) - DAX | Microsoft Learn
Power BI Userelationship function with example - Learn DAX
Using two or more USERELATIONSHIPs - Microsoft Power BI Community
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @jeffrock ,
Please try this measure.
Count = CALCULATE(
DISTINCTCOUNT(DEADLINE[WI_ID]),
USERELATIONSHIP(ROUTES[Assigned_Vehicle], DEADLINE[INSTANCE_NUMBER]),
USERELATIONSHIP(ROUTES[Date2], DEADLINE[DATE_RELEASED]),
USERELATIONSHIP(ROUTES[Date2], DEADLINE[Date_Delivered2]),
FILTER(
ALL(DEADLINE),
max(ROUTES[Assigned_Vehicle]) = max(DEADLINE[INSTANCE_NUMBER]) &&
max(ROUTES[Date2]) > max(DEADLINE[DATE_RELEASED]) &&
max(ROUTES[Date2] )<max( DEADLINE[Date_Delivered2])
)
)
You can refer to the following documents that may be helpful to you:
USERELATIONSHIP function (DAX) - DAX | Microsoft Learn
Power BI Userelationship function with example - Learn DAX
Using two or more USERELATIONSHIPs - Microsoft Power BI Community
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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