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Hi,
I have an issue where I have a report with many ID’s all ID’s also have identification which is not unique. The identification is what is used as PK in my measure table with many registrations per identification. All ID’s have a registration date and I use that to find project start date. Problem occurs when same identification is used in more than one project and the min registration date is prior to project start date. I created a calculated column in my measure table to find if its in project or not, but this can only see the identification and does not know which of them is in a project.
Is there a way to use a measure or create a measure that says if my ID is in project or not, and then only show data on or after that date in a report. Right now I'm using InProject from measure table, which like I've said is wrong for some projects.
My Project start measure is just: Project Start = min(ID_registration[date_reg])
Below is my relationsship view to make it clearer what my problem is.
This report page shows that my filter is wrong and i need to create a measure or something to apply as a filter to only see values after this particular project start.
My registration with Identification gjd123 has ID 10 and 4:
Thanks!
Solved! Go to Solution.
Hi @Anonymous ,
I'm sorry, i didn't get the point.
You want calculated the min date for project has multiple ids and the id should exists in id table?
Like this?
Measure = CALCULATE(MIN('Table'[date]),FILTER('Table','Table'[id]=SELECTEDVALUE('id'[id])))
Best Regards,
Jay
Community Support Team _ Jay Wang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Anonymous ,
I'm sorry, i didn't get the point.
You want calculated the min date for project has multiple ids and the id should exists in id table?
Like this?
Measure = CALCULATE(MIN('Table'[date]),FILTER('Table','Table'[id]=SELECTEDVALUE('id'[id])))
Best Regards,
Jay
Community Support Team _ Jay Wang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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