Forum Discussion
Unpivot Table
Hi,
I have a bit of strange request not sure if it is possible but I am giving it a try.
I have the following table,
Is there a way I can duplicate the row, and put technology-2 under technology-1, product-2 under product-1?
In other way, can I have a single column for " Product", "Technology" and "Skill" and populating tech-1 and tech-2 under it?
So in that case, each single row will have two rows.
thanks,
5 Replies
- MarcelBeugCommunity Champion
It is not such a strange request; I have seeen such requests before.
I assume you have other columns in your table as well, so I added a "Name" column that represents all those columns.
Steps:
- Select all columns that are not displayed in your picture
- Choose Transform - Unpivot - Other Columns
- Select column "Attribute"
- Choose Transform - Extract - Text Before Delimiter - Delimiter "-", the last delimiter from the end
- Choose Add Column - Add Index Column
- Select column "Index"
- Choose Transform - Standard - Integer-Divide, value 3
- Select column "Attribute"
- Choose Transform - Pivot Column - Values column "Value" - advanced option Don't Aggregate
- Remove column Index
Generated code:
let Source = Table1, #"Unpivoted Other Columns" = Table.UnpivotOtherColumns(Source, {"Name"}, "Attribute", "Value"), #"Extracted Text Before Delimiter" = Table.TransformColumns(#"Unpivoted Other Columns", {{"Attribute", each Text.BeforeDelimiter(_, "-", {0, RelativePosition.FromEnd}), type text}}), #"Added Index" = Table.AddIndexColumn(#"Extracted Text Before Delimiter", "Index", 0, 1), #"Integer-Divided Column" = Table.TransformColumns(#"Added Index", {{"Index", each Number.IntegerDivide(_, 3), Int64.Type}}), #"Pivoted Column" = Table.Pivot(#"Integer-Divided Column", List.Distinct(#"Integer-Divided Column"[Attribute]), "Attribute", "Value"), #"Removed Columns" = Table.RemoveColumns(#"Pivoted Column",{"Index"}) in #"Removed Columns"- abukapsounPost Patron
Thank you very much Marcel for this interesting walkthrough, I have applied the steps but I feel there is something not correct with the alignment.
If I am not mistaken, I haven't seen we have used the index and index/3 columns in the step that follow..
Here is the generated code.
Thank you again,
- abukapsounPost Patron
Hi Marcel,
Sorry for bothering again, but were you able to have a look at the below?
Thanks again