Forum Discussion
Unpivot Duplicates into Single Row
Hi,
How can I get this:
| Column 1 | Column 2 |
| A | 5 |
| A | 8 |
| B | 3 |
| B | 4 |
| C | 3 |
| C | 4 |
| D | 6 |
| D | 1 |
Into this:
| Column 1 | Column 2 | Column 3 |
| A | 5 | 8 |
| B | 3 | 4 |
| C | 3 | 4 |
| D | 6 | 1 |
Thank you
Hi Anonymous
please paste the code into the advanced editor and follow the steps:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTJVitWBsCzALCcgyxjOMgGznOFiznAxFyDLDM4yVIqNBQA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [#"Column 1" = _t, #"Column 2" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column 1", type text}, {"Column 2", Int64.Type}}), #"Grouped Rows" = Table.Group(#"Changed Type", {"Column 1"}, {{"partition", each Table.AddIndexColumn(_, "Index", 1,1)}}), #"Expanded partition" = Table.ExpandTableColumn(#"Grouped Rows", "partition", {"Column 2", "Index"}, {"Column 2", "Index"}), #"Pivoted Column" = Table.Pivot(Table.TransformColumnTypes(#"Expanded partition", {{"Index", type text}}, "en-GB"), List.Distinct(Table.TransformColumnTypes(#"Expanded partition", {{"Index", type text}}, "en-GB")[Index]), "Index", "Column 2") in #"Pivoted Column"I'm creating a nested index to determine the column number like described here: https://www.youtube.com/watch?v=-3KFZaYImEY
4 Replies
- ImkeF
Community Champion
Hi Anonymous
will there always just be 2 columns or will the number of rows/columns change?
Hi ImkeF
There would be more columns in a scenario where there are more than 2 duplicates, which is fine. For example, if there are 3 G values, it's okay for there to be a fourth column that is mostly null except for row G.
- ImkeF
Hi Anonymous
please paste the code into the advanced editor and follow the steps:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTJVitWBsCzALCcgyxjOMgGznOFiznAxFyDLDM4yVIqNBQA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [#"Column 1" = _t, #"Column 2" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column 1", type text}, {"Column 2", Int64.Type}}), #"Grouped Rows" = Table.Group(#"Changed Type", {"Column 1"}, {{"partition", each Table.AddIndexColumn(_, "Index", 1,1)}}), #"Expanded partition" = Table.ExpandTableColumn(#"Grouped Rows", "partition", {"Column 2", "Index"}, {"Column 2", "Index"}), #"Pivoted Column" = Table.Pivot(Table.TransformColumnTypes(#"Expanded partition", {{"Index", type text}}, "en-GB"), List.Distinct(Table.TransformColumnTypes(#"Expanded partition", {{"Index", type text}}, "en-GB")[Index]), "Index", "Column 2") in #"Pivoted Column"I'm creating a nested index to determine the column number like described here: https://www.youtube.com/watch?v=-3KFZaYImEY