Forum Discussion
Un-cumulate Cumulative Values
- 7 years ago
BjoernSchaefer Here is the steps I've followed to solve this.
Step 1 : Add an Index Column (start from 1) in "Power Query"
Step 2 : Add an additional column using "New Column" as below
RankAccount = RANKX(FILTER(Test04UnCumm,Test04UnCumm[Account]=EARLIER(Test04UnCumm[Account]) && Test04UnCumm[Date] = EARLIER(Test04UnCumm[Date])),Test04UnCumm[Index],,ASC)
Step 3 : Finally, here is the magical column we are looking for
UnCummVal = VAR _PrevCummVal = LOOKUPVALUE(Test04UnCumm[CummVal],Test04UnCumm[Account],Test04UnCumm[Account],Test04UnCumm[Date],Test04UnCumm[Date]-1,Test04UnCumm[RankAccount],Test04UnCumm[RankAccount]) RETURN IF(_PrevCummVal=BLANK(),Test04UnCumm[CummVal],Test04UnCumm[CummVal] - _PrevCummVal)
The output will be as below :
Uhhh !! Nice one :-)
BjoernSchaefer Could you please post the sample data (Copiable format) and expected output which will help to understand the issue bit more detail.
- BjoernSchaefer7 years agoHelper II
AccountDateValue CumulativeDescriptionExpected OutcomeDescription2
1753 01.01.2017 157 <- These are the running totals by month 157 1753 01.01.2017 152 152 1753 01.01.2017 177 177 1753 01.01.2017 120 120 1753 01.01.2017 138 138 1753 01.01.2017 129 129 1753 01.01.2017 141 141 1753 01.01.2017 118 118 1753 01.01.2017 175 175 1446 01.01.2017 137 137 1446 01.01.2017 181 181 1446 01.01.2017 165 165 1446 01.01.2017 114 114 1446 01.01.2017 165 165 1446 01.01.2017 180 180 1446 01.01.2017 115 115 1446 01.01.2017 128 128 1446 01.01.2017 181 181 1446 01.01.2017 182 182 1446 01.01.2017 190 190 1753 02.01.2017 301 144 <- This is the value i need. It's the difference to January 1st. 1753 02.01.2017 273 121 1753 02.01.2017 367 190 1753 02.01.2017 270 150 1753 02.01.2017 328 190 1753 02.01.2017 267 138 1753 02.01.2017 307 166 1753 02.01.2017 229 111 1753 02.01.2017 364 189 1446 02.01.2017 297 160 1446 02.01.2017 360 179 1446 02.01.2017 296 131 1446 02.01.2017 271 157 1446 02.01.2017 269 104 1446 02.01.2017 302 122 1446 02.01.2017 289 174 1446 02.01.2017 326 198 1446 02.01.2017 371 190 1446 02.01.2017 336 154 1446 02.01.2017 304 114 - PattemManohar7 years agoCommunity Champion
BjoernSchaefer Just to confirm, is this what you are expecting as output in a new table
1753 01.01.2017 157
1753 02.01.2017 144Or you want to display in new column as mentioned above
- BjoernSchaefer7 years agoHelper II
PattemManohar, this is correct. I need an extra column. But i'm not able to figure out how to do that. Thank you very much for your responses.