Forum Discussion
Two slicer to select auto select
Hi All,
I need one logic guys.
I have two slicer in one page and these two slicers have two column of the same table.
If any one slicer is filter the another Slicer is select automatically.
It is Possible? Please help me.
Thanks in advance.
Hi Anonymous
The described interaction is a default. The slicers are filtering each other.If you need it in another way you can do it from format >> edit interactions.
More information about the feature here:
https://www.youtube.com/watch?v=KQsRHWTF4Bs
If this post helps, then please consider Accepting it as the solution to help the other members find it more quickly
Hi Anonymous
No, it can't be selected automatically because the selection needs the click of the user.
But the functionality of filtering works.
If this post helps, then please consider Accepting it as the solution to help the other members find it more quickly
4 Replies
Hello,
Not sure to understand everything but I think you are talking about visuals interactions ! Take a look at that link, it explains very well how to do it : https://learn.microsoft.com/en-us/power-bi/create-reports/service-reports-visual-interactions?tabs=powerbi-desktop
Igna
Hi Ritaf1983 ,
Thanks for your response.This is default slicer condition. In your Snips If i Select Count 2 means That Name slicer is automatically that checkbox is coloured. In this scenario, the name C is unselect but its filtered correctly.
I need to select any count means that name slicer also select automatically.
It is Possible?
Hi Anonymous
No, it can't be selected automatically because the selection needs the click of the user.
But the functionality of filtering works.
If this post helps, then please consider Accepting it as the solution to help the other members find it more quickly
Hi Anonymous
The described interaction is a default. The slicers are filtering each other.If you need it in another way you can do it from format >> edit interactions.
More information about the feature here:
https://www.youtube.com/watch?v=KQsRHWTF4Bs
If this post helps, then please consider Accepting it as the solution to help the other members find it more quickly
