Forum Discussion

Kostas's avatar
Kostas
Helper IV
4 years ago
Solved

TopN First Value based on Count in another table

Hello,    I am kind of stuck in something that I feel is easy to solve and I need your help (once again).  I got two tables connected with a relationship 1 to many like the below: Table 1 ID ...
Need Help
  • Kostas's avatar
    Kostas
    4 years ago

    Managed at least to find how to syntax the formula based on the answer amitchandak gave me. 

     

    Top Reason Card = 
Calculate all the available ID's in table1
Var NumberofID = 
DISTINCTCOUNT(table1[ID])
// return the reason with the biggest count of ID's (first ask)
Var TopReason = 
CALCULATE(
    MAX(table2[Reason Name]), topn(1, ALLSELECTED(table2[Reason Name]), calculate(COUNT(table1[ID])), DESC), VALUES(table2[Reason Name])
)
// calculate the count of ID's under the reason with the biggest count (ask 2)
Var CalcReference = CALCULATE(DISTINCTCOUNT(table1[ID]), table2[Reason Name] = TopReason)
// calculate the percentage in comparison to the total population (ask 3) 
Var PercReference = FORMAT(CalcReference/NumberofID,"##%")

Return 
Var TopReason & " - " & CalcReference  & " / " & CalcReference 
// that will return 
Name 2 - 2 / 50%

     

amitchandak's avatar
amitchandak
Super User
4 years ago

Kostas , Try a measure like

 

CALCULATE(concatenatex(Table, Table[ID]) ,TOPN(1,allselected(Table2[Reason Name]),calculate(Count(Table1[ID])),DESC),VALUES(Table2[Reason Name]))

  • Kostas's avatar
    Kostas
    Helper IV
    4 years ago

    Hello amitchandak 
    It seems that the measure returns a concatenation of all the ID's from the first table that refer to the reason with most ID's assigned to it. 
    I need the card to return the "Reason" that has the biggest population in terms of count of ID from the table 1 (as shown above the Reason Name 2 has 2 ID's assigned to it compared with the other reasons that have only 1. 
    Also, another measure that will return to me the count of ID's that are assigned to the reason that has the most (as mentioned above the number will be 2).

    I hope that helps