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Anonymous's avatar
Anonymous
Not applicable
6 years ago
Solved

To calculate the consecutive differences with the specific value chosen using FILTERS and Date slice

Hi folks,

 

I need help in calculating the cosecutive differences between rows with first rows fixed everytime with date slicer and Fund name. The calculations are as follows. Please help me.

 

READY COLUMNTo Calculate the NEW Columns  
  
SnoFundReturnPriceDateStart (Sno = 3)  
1A0.081081/1/2019   
2A-0.06101.521/2/2019  Calculations - 
3A0.06107.61121/3/2019   
4A-0.196.850081/4/2019-0.11To Fix the minimum value from COL-F based on minimum date of the slicer and "Fund A"
5A0.0399.75558241/5/2019-0.0732For next all the filtered entries -  take the differences from the first value of the column D baesed on the FILTERS of date and FUND(HIGHLIGHTED one)
6A0.1109.73114061/6/20190.0197 
7A-0.01108.63382921/7/20190.009503  
8A0.03111.89284411/8/20190.03978809  
9A-0.03108.53605881/9/20190.008594447  
10A0.05113.96286171/10/20190.05902417  
11A-0.02111.68360451/11/20190.037843686  
12A0.02113.91727661/12/20190.05860056  
13A0.07121.89148591/13/20190.132702599  
14D0.031031/1/2019  Same calculations for this fund also
15D-0.0498.881/2/2019  
16D0.02100.85761/3/2019  
17D-0.0298.8404481/4/2019-0.040384 
18D-0.0989.944807681/5/2019-0.12674944 
19D0.0493.542599991/6/2019-0.091819418 
20D-0.0886.059191991/7/2019-0.164473864 
21D-0.0780.035048551/8/2019-0.222960694 
22D0.0886.437852431/9/2019-0.160797549  
23D0.0994.217259151/10/2019-0.085269329  
24D0.0397.043776931/11/2019-0.057827408  
25D0.08104.80727911/12/20190.017546399  
26D0.09114.23993421/13/20190.109125575  
  • Anonymous's avatar
    Anonymous
    6 years ago

    Thanks for your reply. I got the solution.

2 Replies

  • Hi Anonymous ,

    I'm a little confused by your description. Could you please share more detailed calculation logic for the "Start" column?

    Best Regards,

    Community Support Team _ Joey
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

    • Anonymous's avatar
      Anonymous
      Not applicable

      Thanks for your reply. I got the solution.