Forum Discussion
Matho101
4 years agoNew Member
Time intelligence - Month and Year Issue
Hi, New user so apologies for the ignorence. I am looking at using time intelligence to calculate Sales performance for Year on Year (total) & also Month vs Month. Problem is my sales d...
- 4 years ago
Hi, Matho101 ;
You could create a column as follow:
Column = MONTH ( [MONTH] & " 1" )The final output is shown below:
Or create a column :
date = DATE([YEAR], MONTH ( [MONTH] & " 1" ),1)The final output is shown below:
Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Samarth_18
4 years agoCommunity Champion
Hi Matho101 ,
Try this:-
Date =
var _month = SWITCH([month],"Jan",1,
"Feb",2,
"Mar",3,
"Apr",4,
"May",5,
"Jun",6,
"Jul",7,
"Aug",8,
"Sep",9,
"Oct",10,
"Nov",11,
"Dec",12)
return DATE([Year],_month,1)
Output:-
Thanks,
Samarth