Forum Discussion
Summarized slicer
- Anonymous6 years ago
For finishing this post, we need to mark an answer as a sloution.
So here I will copy my answer in Dimensions filtered by summarized measure values and mark it as a solution.
I use measure to achieve your goal.
Measure1:
Measure1 = CALCULATE(SUM(Query1[All Quotes]),FILTER(ALL(Query1),Query1[Mar_Desc]=MAX(Query1[Mar_Desc])))Measure2:
Measure2 = IF( [Measure1]<= MAX(Query1[Rank by category]),[Measure1],BLANK())We build a new table visual by Mar_Desc and Measure2. Then select 231830 in Slicer.
Result is as below:
You can download the pbix file from this link: Dimensions filtered by summarized measure values
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Your problem may have been solved in your new community. Link: Dimensions filtered by summarized measure values
Please kindly Accept it as the solution. More people will benefit from it. Or you are still confused about it, please provide me with more details about your problem or share me with your pbix file from your onedrive business.
Best Regards,
Rico Zhou
Hi Anonymous - yes I've accepted the solution for : Dimensions filtered by summarized measure values - thank you very much for your help !
- Anonymous6 years agoNot applicable
For finishing this post, we need to mark an answer as a sloution.
So here I will copy my answer in Dimensions filtered by summarized measure values and mark it as a solution.
I use measure to achieve your goal.
Measure1:
Measure1 = CALCULATE(SUM(Query1[All Quotes]),FILTER(ALL(Query1),Query1[Mar_Desc]=MAX(Query1[Mar_Desc])))Measure2:
Measure2 = IF( [Measure1]<= MAX(Query1[Rank by category]),[Measure1],BLANK())We build a new table visual by Mar_Desc and Measure2. Then select 231830 in Slicer.
Result is as below:
You can download the pbix file from this link: Dimensions filtered by summarized measure values
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- richard_wylde6 years agoHelper IV
Hi Anonymous - sure, thanks that's great