Forum Discussion
Sum of Measure is wrong
Hi all,
I was trying to come up with a measure to sum up the amount. It returns the correct number for each row, however, the total is not correct. Does anyone know how to go about doing it?
Measure = IF(DISTINCTCOUNT('Table'[Merged])>1,DIVIDE(sum('Table'[Amount]),DISTINCTCOUNT('Table'[Merged])),SUM('Table'[Amount]))
Table:
| Amount | Booked | Merged |
| 1734887.59 | 32148653 | 2016-38736 1 001001006 |
| 1734887.59 | 32148653 | 2016-38737 1 001001006 |
| 484259 | 32148944 | 2016-39663 1 001013000 |
| 2656296 | 32175943 | 2017-103708-3 1 001001020 |
| 2261870 | 32175948 | 2017-103708-3 2 S001001002 |
Here is the link of the pbix sample:
https://drive.google.com/open?id=10hGBZUKJ2ud9CtUpjOs6WQIQvKMvgaZw
Thank you!
JPY
4 Replies
- AnonymousNot applicable
Hi, I understand your confusion.
The calculation for total is represented by your measure:
DIVIDE ( 8.872.200,18 / 5 )Gives you 1.774.440,04; which is correct!
Basically adding your original "Amount", will help here to understand your problem.
- amitchandak
Super User
Try
Measure = sumx(summarize('Table','Table'[Booked],"_sum",sum('Table'[Amount]),"_dist",DISTINCTCOUNT('Table'[Merged])) if(_dist>1 , divide(_sum,_dist),_sum))Appreciate your Kudos. In case, this is the solution you are looking for, mark it as the Solution. In case it does not help, please provide additional information and mark me with @
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Resident Rockstar
Hi Anonymous ,
I think this is an issue of granularity of the data at the row level of the table the data is calculated correctly, however at the grand total the distinct counts are all 1, if you create t following measures you will see how you can make the total work properly with sumx
dist_count = DISTINCTCOUNT('Table'[Merged])divide_by_dist = if(DISTINCTCOUNT('Table'[Booked]) = 1, [Measure], sumx(VALUES('Table'[Booked]),[measure])/[dist_count]) - AnonymousNot applicable
Hi Anonymous ,
The total isn't the sum of the measure, it's the result of all amount being calculated by your formula.
Best Regards,
Jay
Community Support Team _ Jay Wang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.