Forum Discussion
String Extract based on criteria
I have a table and one column contains free text. I'm looking to add a column which will search the free text and extract anything which has a letter followed by 5 numbers.
For example - the below would be extracted:
D98765
d12345
D 54821
d 65411
This could be anywhere within the string of text. Is this possible?
mwild ***Made a tweak to the code***
The following works. I will let you tweak the code further if you need to so I am not doing all your homework 😂
StringMatch = VAR NoBlankFreeText = SUBSTITUTE ( 'Sample Data'[FreeText], " ", "", 1 ) VAR UpperD = FIND ( "D", NoBlankFreeText, 1, BLANK () ) VAR LowerD = FIND ( "d", NoBlankFreeText, 1, BLANK () ) VAR PositionD = IF ( ISNUMBER ( UpperD ), UpperD, LowerD) VAR CheckNumbers = ISERROR ( ISNUMBER ( VALUE ( MID ( NoBlankFreeText, PositionD + 1, 5 ) ) ) ) RETURN IF ( NOT ( CheckNumbers ), MID ( NoBlankFreeText, PositionD, 6), "No Match" )
7 Replies
You can do this using regular expression (using R or Python) in the query editor, Curbal here explains it really well
https://www.youtube.com/watch?v=9E3VsvFAge4
Regards,
Moiz
If this post helps, please "Accept" it as Solution to help other members find it.
You can use CONTAIN function
Or you can use CONTAINSSTRING function e.g
MyCalculatedColumn = If(CONTAINSSTRING([TARGETCOLUMN];"searchforthis");TRUE();FALSE())
I am not sure how this will work when the end goal is "any letter followed by any numbers" when the letter and the numbers could be anything, e.g. it can be "Z 98765" or "b34561" or worse "!@#@!D48202@#!@".
The letter will always be "D" or "d"
There may be a space (or may not be) and then 5 numbers between 0 and 9
With combination of LEFT or RIGHT function
