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Anonymous
Not applicable

Simple calculation

Hi, all.

 

I wonder how to make a measure value in this case.

I want to count the rowss of tablet A with filter about A,B,C.
I want to calculate by applying a filter for the state of B and the version of C.
The three table Relations are as follows.

HUAM_0-1644801457184.png

I tried likt this but no work

#test =
CALCULATE(COUNTROWS('A'),
   'A'[A_type] = "A_type" &&
   'A'[A_status] = "A_status" &&
   'B'[B_status] = "B_status" &&
   'C'[C_type = "C_type")
 
I think it isn't work beacause of many to many realtion.
How to calculation in this case?
 
Thank you
1 ACCEPTED SOLUTION
v-yalanwu-msft
Community Support
Community Support

Hi, @Anonymous ;

I noticed your last post, is it similar to this one, based on the data from the previous post, I created the following formula:

diff = DATEDIFF(MAX('Table'[coupon_usedate]),MAX('Table2'[lastlinkdate]),DAY)
count = COUNTX(FILTER( 'Table2',[diff]<=30&&[diff]>=0),[lastlinkdate])

 The final output is shown below:

vyalanwumsft_0-1645079645567.png

If not right ,could you share a simple file and share the result what you want to output?


Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-yalanwu-msft
Community Support
Community Support

Hi, @Anonymous ;

I noticed your last post, is it similar to this one, based on the data from the previous post, I created the following formula:

diff = DATEDIFF(MAX('Table'[coupon_usedate]),MAX('Table2'[lastlinkdate]),DAY)
count = COUNTX(FILTER( 'Table2',[diff]<=30&&[diff]>=0),[lastlinkdate])

 The final output is shown below:

vyalanwumsft_0-1645079645567.png

If not right ,could you share a simple file and share the result what you want to output?


Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Ashish_Mathur
Super User
Super User

Hi,

You should not have many to many relationships at all.  You should use/create a bridge table instead.  Share some data to work with along with a description of your question and show the expected result.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

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