Forum Discussion
Show Changes between two given periods
- 8 years ago
Hi Aroth,
Measure = CALCULATE([net]),FILTER(ALL(MONTHS),MONTHS[index] = MAX(MONTHS[index]))-CALCULATE([net]),FILTER(ALL(MONTHS), MONTHS[index] = MIN(MONTHS[index] )Based on above measure, I could get the desired output.
What we need is add a MonthNo column to original table (suppose it's 'Month-Project'), and insert an extra table (in my test, it's named as 'Month') listing unique month values.
Create measure like:
Diff = CALCULATE ( ( [net] ), FILTER ( 'Month-Project', 'Month-Project'[MonthNo] = MAX ( 'Month'[MonthNo] ) ) ) - CALCULATE ( ( [net] ), FILTER ( 'Month-Project', 'Month-Project'[MonthNo] = MIN ( 'Month'[MonthNo] ) ) )Add field [Month] from 'Month' table. Add [Project] and [Diff] from 'Month-Project' table.
Best regards,
Yuliana Gu
I think that if you use EXCEPT along with a UNION and a NATURALINNERJOIN that you could essentially return a table with all of your exceptions. So the NATURALINNERJOIN would find the matching rows between the tables. UNION would UNION your tables together and so if you take the EXCEPT of the UNION and NATURALINNERJOIN you would have the differences.
- Aroth8 years ago
Advocate II
Greg_Deckler thank you for answer, I'm not sure how I can use that as everything is on the same data base (table):
Month Project net October P1 12 October P2 5 October P3 5 December P2 6 December P3 4 December P4 10 That's why I use CALCULATE to filter on one month and substract by another CALCULATE filtered on an other month.
And my "net" field is a measure...- Greg_Deckler8 years ago
Community Champion
Wow, I way over complicated that. Just create a measure:
Measure = CALCULATE(SUM(Projects[net]),Projects[Month]="December")-CALCULATE(SUM(Projects[net]),Projects[Month]="October")
Then put your Project column and this measure into a Table visualization.
- Aroth8 years ago
Advocate II
That's what I did, the only thigs Iv'e added is :
Measure = CALCULATE([net]),FILTER(ALL(MONTHS),MONTHS[index] = MAX(MONTHS[index]))
-CALCULATE([net]),FILTER(ALL(MONTHS), MONTHS[index] = MIN(MONTHS[index] )
So it enable to compare two selected periods ...
- Anonymous4 years agoNot applicable
Can you kindly elaborate more with the simple data set provided by requester. Also can you help how to solve it with drill through