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Anonymous's avatar
Anonymous
Not applicable
7 years ago
Solved

SUMX Distinct and GroupBy

Hi I have a table with Month, Week and number of records. What I would like to do is Sum(Distinct(Records)) groupby MonthNo, WeekNo.   I have a join with another table using MonthNo and WeekNo. So ...
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  • v-jiascu-msft's avatar
    v-jiascu-msft
    7 years ago

    Hi Anonymous ,

     

    The correct result should be 10085. There could be two solutions. The basic idea is including the MonthNo and WeekNo at the same time. 

    Measure 2 =
SUMX ( ALL ( DB[MonthNo], DB[WeekNo] ), CALCULATE ( MAX ( DB[Records] ) ) )

    Measure 3 =
SUMX (
    SUMMARIZE ( DB, DB[MonthNo], DB[WeekNo], "maxRecords", MAX ( DB[Records] ) ),
    [maxRecords]
)

    SUMX-Distinct-and-Group-By

     

    Best Regards,

v-jiascu-msft's avatar
v-jiascu-msft
Icon for Microsoft Employee rankMicrosoft Employee
7 years ago

Hi Anonymous ,

 

Actually, this formula "RecordsMeasure = MAXX(DISTINCT(DB[Records]), MAX(DB[Records]))" equals the one below.

 

RecordsMeasure = MAX(DB[Records])

What are the values of DB[Records]? Can we calculate a Max value?

 

Generally, the results base on MonthNo or WeekNo are different. Do you mean you'd like to SUM them base on MonthNo and WeekNo?

Can you share a sample, please? Please mask the sensitive parts first.

 

 

Best Regards,

Anonymous's avatar
Anonymous
Not applicable
7 years ago

v-jiascu-msft 

 

Thanks for your reply.

 

Yes I need to calculate the sum distinct by Monthno and weekno. Please see attached data set. Its basically MonthNo, WeekNo and actual values.

 

Please see link to data file on OneDrive with DB[Records] values

 

https://1drv.ms/x/s!AtGoFMN86r67ll-mnGmniDknC2zp

 

 

 

  • v-jiascu-msft's avatar
    v-jiascu-msft
    Icon for Microsoft Employee rankMicrosoft Employee
    7 years ago

    Hi Anonymous ,

     

    The correct result should be 10085. There could be two solutions. The basic idea is including the MonthNo and WeekNo at the same time. 

    Measure 2 =
SUMX ( ALL ( DB[MonthNo], DB[WeekNo] ), CALCULATE ( MAX ( DB[Records] ) ) )

    Measure 3 =
SUMX (
    SUMMARIZE ( DB, DB[MonthNo], DB[WeekNo], "maxRecords", MAX ( DB[Records] ) ),
    [maxRecords]
)

    SUMX-Distinct-and-Group-By

     

    Best Regards,

    • Anonymous's avatar
      Anonymous
      Not applicable
      7 years ago

      Thanks v-jiascu-msft  got the desired result now.