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NewData
Frequent Visitor

Return first value in given hour range over multiple dates

Hello,

I am trying to only return a "1" when a particular model reaches certain set of ranges.

Currently, my data keeps returning duplicates. Returns 1 each time that unit is in that range. 


Example

Important ranges are from 10-15 and 20-25. Each time that unit hits return "1" the first time based on dates. Below table shows Quarters (Q1-Q3), Model, Value equals Hour range. Last column is desired results. 

Untitled.jpg

 

 

 

 

 

 

 

Thanks in advance for help

 

2 ACCEPTED SOLUTIONS
Anonymous
Not applicable

Hi @NewData ,

If you want to chenge the measure to a column, please have a try.

column=
var _min=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=10||value<=15)&&value>=20||value<=25))),table[date])
return 
if(table[date]=_min,1,0)

If I have misunderstood your meaning, please provide the output you want in the form of a picture.

 

Best Regards
Community Support Team _ Polly

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

NewData
Frequent Visitor

@Anonymous 

 

I was able to modify your code to get desired solution

column=
var _min1=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=10&&value<=15))),table[date])
var _min2=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=20&&value<=25))),table[date])
return
if(table[date]=_min1,1,

    If(table[date]=_min2,1,

0))

Thank you for assistance.

View solution in original post

7 REPLIES 7
NewData
Frequent Visitor

@Anonymous 

 

I was able to modify your code to get desired solution

column=
var _min1=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=10&&value<=15))),table[date])
var _min2=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=20&&value<=25))),table[date])
return
if(table[date]=_min1,1,

    If(table[date]=_min2,1,

0))

Thank you for assistance.

NewData
Frequent Visitor

@amitchandak , thank you for the assistance.  I used your code and it return "1" for only first instance, but not second range on another date. 

Anonymous
Not applicable

Hi @NewData ,

Please refer to my pbix file to see if it helps you.

Create a measure.

meausre(first value not in range) =
IF (
    (
        MAX ( 'Table'[value] ) >= 10
            && MAX ( 'Table'[value] ) < 15
    )
        || (
            MAX ( 'Table'[value] ) >= 20
                && MAX ( 'Table'[value] ) < 25
        ),
    1,
    0
)

vpollymsft_0-1653960184838.png

 Best Regards
Community Support Team _ Polly

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

@Anonymous ,

 When applying to entire dataset, it would return a 1 on same Model for each date it's in the range. I would like it to only show a "1" when it's the first instance in the range. 

amitchandak
Super User
Super User

@NewData , Try a meausre like

 

new meausre =
var _min = minx(filter(allselected(Table), Table[Model] = max(Table[Model]) && (([Value] >=10 && [Value] <=15) || ([Value] >=20 && [Value] <=25))), Table[Date])
return
if( Max(Table[Date]) = _min, 1, 0)

@amitchandak , I was able to get your code to return values for each instance by adding more variables for each measure.  
i would like modify this measure to be a column in the table. Any advice on how to make this measure work for NEW COLUMN

Anonymous
Not applicable

Hi @NewData ,

If you want to chenge the measure to a column, please have a try.

column=
var _min=minx(filter(allselected(table),table[model=earlier(table[model])&&((value>=10||value<=15)&&value>=20||value<=25))),table[date])
return 
if(table[date]=_min,1,0)

If I have misunderstood your meaning, please provide the output you want in the form of a picture.

 

Best Regards
Community Support Team _ Polly

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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