Removing an outlier from daily revenue to create average daily revenue over 30 days

[Anonymous]

I have a table that totals our daily revenue with a date. I use the following formula to give me a avg daily revenue over 30 days.

However because February only has 28 days, the last day in February included the payments for what would be the 29th, 30th and 31st of normal months, essentially we got up to 4 days of payments into one so it is artificailly making the average higher than it should be. Is there an easy way to solve this problem? Thanks in advance! 

date_actual	Sum of Total
20-Feb-22	$31,788.02
21-Feb-22	$33,750.21
22-Feb-22	$31,569.05
23-Feb-22	$32,070.29
24-Feb-22	$34,994.32
25-Feb-22	$35,119.62
26-Feb-22	$33,230.44
27-Feb-22	$36,018.30
28-Feb-22	$96,210.87
1-Mar-22	$25,788.40

[negi007 · Accepted solution]

@Anonymous you can create a new measure like below

New_Total =

var YearStartDate = DATE('Table'[date_actual].[Year],1,1)

var YearEndDate = DATE('Table'[date_actual].[Year],12,31)

var TotalDays = (YearEndDate - YearStartDate) + 1

var IsLeapYear = IF(TotalDays = 366,"Yes","No")

return

if ( and (TotalDays=365,'Table'[date_actual].[Date]=DATE(year(YearStartDate),2,28)),'Table'[Sum of Total]/3,

if ( and(TotalDays=366,'Table'[date_actual].[Date]=DATE(Year(YearStartDate),2,29)),'Table'[Sum of Total]/2,

'Table'[Sum of Total]))

let me know if this method helps you. You can customize your average formula as well 

[Anonymous]

This worked liked a charm, thank you! 

[amitchandak]

@Anonymous , you can check and divide

example

if(day(eomonth(max(date[Date]),0)) in {28,29} , [Sum of Total]/4, [Sum of Total])

[Anonymous]

Thank you for that. Im still a little confused but what is the best way to incorporate it. Here is my formula.

Avg Daily Revenue Over 30 Days = CALCULATE (

SUM (dim_date[amount]),

DATESINPERIOD( dim_date[date_actual], TODAY() -1, -30, DAY )

) / 30