Forum Discussion
Power Query: Create column from cell value in table column
Hi everyone,
I find myself in a bit of a pickle after trying several options without any success. So here I am with a problem that I sincerely hope someone can help me with.
I imported multiple excel files from a folder, each with multiple sheets all formatted the same way.
After some initial transformations, I arrive at a table identifying the name of each sheet from each file [Model Name], and the relative table column [Excel.Data]. Before expanding the table column, I would like to generate a custom column that reads the specific value in a cell within those tables (the same everywhere), specifically the cell E1 in the excel sheets.
In pictures, here is where I arrive.
Problem
And here is what I would like to get.
Expected solution
The similar post I have seen all related to a cell in multiple files but I couldn't find anything about a cell in all sheets of multiple files. As if this adds a level a complexity I cannot seem to be able to untangle by myself.
Any help and suggestion would be greatly appreciated!
Create the new column with this
= Table.SelectColumns([Excel.Data], "Column5"){0}[Column5]That code is based on your image which shows each table has 5 columns, the 5th being called Column5, and the data you want being in the first row of that column.
Regards
Phil
3 Replies
- PhilipTreacySuper User
Create the new column with this
= Table.SelectColumns([Excel.Data], "Column5"){0}[Column5]That code is based on your image which shows each table has 5 columns, the 5th being called Column5, and the data you want being in the first row of that column.
Regards
Phil
- aury_lolaFrequent Visitor
I love it when the solution end up being something much simpler than whatever I was trying. Thank you so much!
- AnonymousNot applicable
Hi,
Based on the description, the method PhilipTreacy provided should be helpful.
You can also view the following document to learn more information.
Operators - PowerQuery M | Microsoft Learn
Best Regards,
Wisdom Wu
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