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I have a dataset that has 3 columns Product, Expiry Date and Report Date.
| Report Date | Product | Expiry Date |
| Dec-21 | PPPT-01 | 25/01/2024 |
| Dec-21 | WEC-54 | 05/06/2023 |
| Dec-21 | ERRE-66 | 23/08/2025 |
| Jan-22 | PPPT-01 | 01/01/2024 |
| Jan-22 | WEC-54 | 05/06/2023 |
| Jan-22 | ERRE-66 | 23/08/2025 |
| Feb-22 | PPPT-01 | 01/01/2024 |
| Feb-22 | WEC-54 | 15/06/2023 |
| Feb-22 | ERRE-66 | 23/08/2025 |
| Mar-22 | PPPT-01 | 25/01/2024 |
| Mar-22 | WEC-54 | 15/06/2023 |
| Mar-22 | ERRE-66 | 23/08/2025 |
What I a trying to do is create a 4th column called difference. This will output the number of days (+/-) the expiry date has changed per product from the previous month.
The current forumula I'm using is this but it's not working, any suggestions would be appreciated.
difference= sum(Data[Expiry Date])-CALCULATE(SUM(Data[Expiry Date]),PREVIOUSMONTH(Data[Expiry Date].[Date]))
Solved! Go to Solution.
@obriaincian , Make sure report_date is date , a new column
new column =
var _date = eomonth([report_date,-1)
var _max = maxx(filter(Table, [Product] =earlier([Product]) && eomonth([report Date],0) =_date ), [Expiry Date] )
return
datediff(_max,[Expiry Date],day)
@obriaincian , Make sure report_date is date , a new column
new column =
var _date = eomonth([report_date,-1)
var _max = maxx(filter(Table, [Product] =earlier([Product]) && eomonth([report Date],0) =_date ), [Expiry Date] )
return
datediff(_max,[Expiry Date],day)
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