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alanhanssen's avatar
alanhanssen
Frequent Visitor
9 years ago
Solved

Percentage one value appears in another table

Hello,

 

I'm new in PowerBI, I'm taking the PowerBI Course in EdX to avoid silly questions but I can't get this solution done.

I have a table Blogs and the Table Photos, I want to show the percentage of Blogs that has photos attached. Blogs Table has no indicator about it. You can only see in Photos table the blog ID which that photo is attached if is attached to a blog.

Any suggestion to display the percentage of blogs that has 1 or more photos?

 

I know the number already by making a distinct count of blog_id in the photo table but I cannot make the Pie chart with the total. 

  • Hello,

    alanhanssen

     

    Use these measures: 

     

    Count_BlogwithPhotos = CALCULATE(DISTINCTCOUNT(Blogs[BlogiD]),RELATEDTABLE(Photos))

     

    Count_NoBlogwithPhotos = DISTINCTCOUNT(Blogs[BlogiD])-[Count_BlogwithPhotos]

     

    Finally, Put both measure in chart values.

     

     

  • Hi, alanhanssen

     

    Create a measure:

    Count_BlogwithPhotos  = CALCULATE(DISTINCTCOUNT(Blog[Blog_ID]),RELATEDTABLE(Photo))

     

    Add a calculated column in Blog table:

    Column 2 = IF(LOOKUPVALUE(Photo[Blog_ID],Photo[Blog_ID],Blog[Blog_ID])=Blog[Blog_ID],"Attached","UnAttached")

    Then, thepie chart should be like:

     

     

    Best regards,
    Yuliana Gu

     

2 Replies

  • Vvelarde's avatar
    Vvelarde
    Icon for Community Champion rankCommunity Champion

    Hello,

    alanhanssen

     

    Use these measures: 

     

    Count_BlogwithPhotos = CALCULATE(DISTINCTCOUNT(Blogs[BlogiD]),RELATEDTABLE(Photos))

     

    Count_NoBlogwithPhotos = DISTINCTCOUNT(Blogs[BlogiD])-[Count_BlogwithPhotos]

     

    Finally, Put both measure in chart values.

     

     

  • v-yulgu-msft's avatar
    v-yulgu-msft
    Icon for Microsoft Employee rankMicrosoft Employee

    Hi, alanhanssen

     

    Create a measure:

    Count_BlogwithPhotos  = CALCULATE(DISTINCTCOUNT(Blog[Blog_ID]),RELATEDTABLE(Photo))

     

    Add a calculated column in Blog table:

    Column 2 = IF(LOOKUPVALUE(Photo[Blog_ID],Photo[Blog_ID],Blog[Blog_ID])=Blog[Blog_ID],"Attached","UnAttached")

    Then, thepie chart should be like:

     

     

    Best regards,
    Yuliana Gu