Forum Discussion
Percentage Calculation
- Anonymous2 years ago
Hi liberty345 ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
Measure = COUNT('Table'[Type2])Measure 2 = SUM('Table (2)'[Value])(2) We can create measures.
Total Measure = CALCULATE([Measure],ALL('Table'))% Measure = DIVIDE([Measure],[Total Measure],0)% = DIVIDE(SUM('Table (2)'[Value]),CALCULATE(SUM('Table (2)'[Value]),FILTER(ALLSELECTED('Table (2)'),'Table (2)'[Type]="Main category")),0)(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- Anonymous2 years ago
The [measure] would be something like [Net Sales]. Here are all the measures:
NetSales = SUM(Sales[SalesAmount])TermPlanPct = DIVIDE([Net Sales], [TermPlanTotal])TermPlanTotal =CALCULATE([Net Sales],All(Sales))
Hi liberty345 ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
Measure = COUNT('Table'[Type2])Measure 2 = SUM('Table (2)'[Value])
(2) We can create measures.
Total Measure = CALCULATE([Measure],ALL('Table'))% Measure = DIVIDE([Measure],[Total Measure],0)% = DIVIDE(SUM('Table (2)'[Value]),CALCULATE(SUM('Table (2)'[Value]),FILTER(ALLSELECTED('Table (2)'),'Table (2)'[Type]="Main category")),0)
(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- liberty3452 years agoRegular Visitor
Thank you so much Anonymous for the solution! 🙂