Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
7 years ago
Solved

Percent Column

I am trying to find percent approved, and having trouble. This is in a table by month and year

 

Year      Month       #Received       # Approved           %Approved

2019     Feb              50                     30                        ????

 

Formula?

  • parry2k's avatar
    parry2k
    7 years ago

    Anonymous yes it will, then you have to add a measure

     

    % Approved = 
    DIVIDE( SUM( Table[Approved] ), SUM( Table[Received] ) )

5 Replies

  • Anonymous is it approved divided by received, add following column and change it to %

     

     

     

    % Approved = DIVIDE( Table[Approve], Table[Received])
    • Anonymous's avatar
      Anonymous
      Not applicable

      That doesn't work - it pulls a percent in the thousands, when it should be around 50% (for the real data).

      • parry2k's avatar
        parry2k
        Super User

        Anonymous doesnt make sense, it should return 0.6 and when you change format to % it would show 60%