Pareto with duplicate values

Question

I'm trying to show a Pareto chart but I have serveral duplicated values; this results in a jagged step function, as PBI is rolling up the multiple occurances as one. For example:

Any ideas to show this properly? For example instead of 9%, 25%, 25% this should show 9%, 17%, 25%.

My cumulative percent function is just rolling up the Score by Business Risk:

Business Risk Cumulative =

var thisProduct=[Score Measure]

var allProducts=calculate([Score Measure],all(JoinMatrix[Business Risk]))

return

calculate([Score Measure],filter(all(JoinMatrix[Business Risk]),[Score Measure]>=thisProduct))/allProducts

mahoneypat · Answer

This one can be done with a two column rank using a pattern like this.&nbsp;
&nbsp;
First make a calculated column to get a rank based on the Risk category with an expression like this.&nbsp; It will give you rank your categories alphabetically.
&nbsp;

ForRiskRank = var thisvalue = Risk[Risk] return RANKX(Risk, Risk[Risk], thisvalue,DESC)
&nbsp;
Then create a measure like this (replace Risk with your actual table name, and correct column/measure references).&nbsp; The alphabetical rank is divided by 1000 so that result can't affect the overall ranking based on risk.&nbsp; Adapt as needed.
&nbsp;
Cumulative&nbsp;Risk&nbsp;Pct&nbsp;=VAR&nbsp;thisvalue&nbsp;=&nbsp;&nbsp;&nbsp;&nbsp;MIN&nbsp;(&nbsp;Risk[Value]&nbsp;)VAR&nbsp;thisriskrank&nbsp;=&nbsp;&nbsp;&nbsp;&nbsp;MIN&nbsp;(&nbsp;Risk[ForRiskRank]&nbsp;)&nbsp;/&nbsp;1000VAR&nbsp;summary&nbsp;=&nbsp;&nbsp;&nbsp;&nbsp;ADDCOLUMNS&nbsp;(&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;ALLSELECTED&nbsp;(&nbsp;Risk[Risk]&nbsp;),&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;"cValue",&nbsp;CALCULATE&nbsp;(&nbsp;MIN&nbsp;(&nbsp;Risk[Value]&nbsp;)&nbsp;),&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;"cRanked",&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;CALCULATE&nbsp;(&nbsp;SUMX&nbsp;(&nbsp;Risk,&nbsp;Risk[Value]&nbsp;+&nbsp;Risk[ForRiskRank]&nbsp;/&nbsp;1000&nbsp;)&nbsp;)&nbsp;&nbsp;&nbsp;&nbsp;)VAR&nbsp;totalvalue&nbsp;=&nbsp;&nbsp;&nbsp;&nbsp;SUMX&nbsp;(&nbsp;summary,&nbsp;[cValue]&nbsp;)VAR&nbsp;cumulativevalue&nbsp;=&nbsp;&nbsp;&nbsp;&nbsp;SUMX&nbsp;(&nbsp;FILTER&nbsp;(&nbsp;summary,&nbsp;[cRanked]&nbsp;&gt;=&nbsp;thisvalue&nbsp;+&nbsp;thisriskrank&nbsp;),&nbsp;[cValue]&nbsp;)RETURN&nbsp;&nbsp;&nbsp;&nbsp;DIVIDE&nbsp;(&nbsp;cumulativevalue,&nbsp;totalvalue&nbsp;)
&nbsp;
&nbsp;
I made a simple table to test it out below.
&nbsp;

&nbsp;

&nbsp;
Pat
&nbsp;

greggbb · Answer

Thanks Pat, but it's returning 100% across the board. I realized that I didn't mention that the dataset is one level below "Business Risk" with a subcategory called "Vulnerabily" so I wonder if this is part of the issue, i.e. my raw data looks like this:

Business Risk	Vulnerability	ScoreCol	Score Measure	Business Risk Cumulative	Overall Total	Cumulative Risk Pct
Customer Order Submission failure	Denial of Service/Network failure	10	10	12%	2174	12%
PII Disclosure	Social Engineering/Phishing	16	16	13%	2174	13%
Order fulfilment stoppage	Ransomware/Malware	15	15	17%	2174	8%
Order Processing stoppage	Ransomware/Malware	15	15	17%	2174	17%

Interestingly in my chart I'm getting 100% when I look at Business Risk alone (it's the dark blue line, the light blue is my original metric):

However if I filter on any aspect of Vulnerability your metric works perfectly! Is there something I can adjust so it will work at both levels?

Thanks,

Gregg

v-kkf-msft · Answer

Hi&nbsp;greggbb&nbsp;,
&nbsp;
Try the following formula:
&nbsp;
&nbsp;
Order = 
VAR RoundedSales = [Score Measure]
RETURN IF (
    HASONEVALUE ( JoinMatrix[Business Risk] ) &amp;&amp; ( RoundedSales &gt; 0 ),
    VAR CustomersWithRankedName =
        ADDCOLUMNS (
            ALLSELECTED ( JoinMatrix ),
            "@NameRanked", RANKX ( ALLSELECTED ( JoinMatrix ), JoinMatrix[Business Risk],, DESC, DENSE )
        )
    VAR MaxCustomerNameRanked =
        MAXX ( CustomersWithRankedName, [@NameRanked] )
    VAR LookupTable =
        ADDCOLUMNS (
            CustomersWithRankedName,
            "@CustomerSales",
                [Score Measure] * MaxCustomerNameRanked + [@NameRanked]
        )
    VAR CurrentName =
        SELECTEDVALUE ( JoinMatrix[Business Risk] )
    VAR CurrentNameRanked =
        RANKX ( ALLSELECTED ( JoinMatrix ), JoinMatrix[Business Risk], CurrentName, DESC, DENSE )
    VAR CurrentValue = RoundedSales * MaxCustomerNameRanked + CurrentNameRanked
    VAR Ranking =
        RANKX ( LookupTable, [@CustomerSales], CurrentValue,, DENSE )
    RETURN
        Ranking
)Business Risk Cumulative = 
var thisProduct = [Score Measure]
var allProducts = calculate( [Score Measure], all(JoinMatrix[Business Risk] ) )
var maxCurrentRank = [Order]
var rankTable = FILTER( ALLSELECTED(JoinMatrix[Business Risk]), [Order] &lt;= maxCurrentRank)
return CALCULATE([Score Measure], rankTable) / allProducts
&nbsp;
&nbsp;
Referencing:&nbsp;https://www.sqlbi.com/articles/rankx-on-multiple-columns-with-dax-and-power-bi/&nbsp;
&nbsp;
&nbsp;
If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

greggbb · Answer

Thanks Winniz, but that isn't working either.&nbsp; In fact it's all coming in at 98%:&nbsp;&nbsp;This has become oddly complicated for something that I can easily build in Excel.&nbsp; I'm going to look for a different visualization to get my point across as it doesn't seem Power BI can handle the math when duplication is involved.&nbsp;Thanks,Gregg&nbsp;

v-kkf-msft · Answer

Hi&nbsp;greggbb&nbsp;,
&nbsp;
Could you please share your PBIX file without sensitive data? In my test data, it works well.
&nbsp;

&nbsp;
If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
Best Regards,Winniz
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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Pareto with duplicate values

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