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Pavel_Ischenko's avatar
Pavel_Ischenko
Regular Visitor
4 years ago
Solved

Orthogonal filtering

Hello guys! Is there anybody knows how to implement so called "orthogonal" filtering in PBI. What I mean here. This is data visual. There are hundreds of products tested in hundreds locations. In t...
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  • Anonymous's avatar
    Anonymous
    4 years ago

    Hi Pavel_Ischenko ,

     

    Try to create this measure

    Measure = 
VAR _count =
    CALCULATE (
        COUNT ( 'Table'[Result] ),
        FILTER ( ALLSELECTED ( 'Table' ), [TRILD] = MAX ( 'Table'[TRILD] ) )
    )
VAR _count2 =
    CALCULATE ( DISTINCTCOUNT ( 'Table'[HGHNM] ), ALLSELECTED ( 'Table' ) )
RETURN
    IF ( ISFILTERED('Table'[HGHNM])&&_count = _count2, 1 )

    Then put the measure into Filters and set as follows

    When filtering, see the results

     

    Best Regards,

    Stephen Tao

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

AlexisOlson's avatar
AlexisOlson
Super User
4 years ago

What do your data table(s) look like?

Pavel_Ischenko's avatar
Pavel_Ischenko
Regular Visitor
4 years ago

Hello.

Table is like

 

  • AlexisOlson's avatar
    AlexisOlson
    Super User
    4 years ago

    Create a new calculated table to use as your slicer and column values for the matrix.

    Slicer  = VALUES ( Table1[HGHNM] )

     

    Then define a measure to check whether the set of selected products is the same as the set of products for the given TRLID.

    ResultSliced =
VAR SlicerValues = ALLSELECTED ( Slicer[HGHNM] )
VAR TRLValues = VALUES ( Table1[HGHNM] )
VAR SharedCount = COUNTROWS ( INTERSECT ( SlicerValues, TRLValues ) )
RETURN
    IF (
        COUNTROWS ( SlicerValues ) = SharedCount && COUNTROWS ( TRLValues ) = SharedCount,
        CALCULATE ( SUM ( Table1[Result] ), Table1[HGHNM] IN VALUES ( Slicer[HGHNM] ) )
    )

     

    Note: I check set equality here by taking the intersection of the two sets and checking if that has the same cardinality as each of the sets being intersected. If both A and B only contain values from A ∩ B, then these sets much be equal.