Forum Discussion
Not filtering correct in UNION
Hello all,
Maybe this is an easy take, but I'm facing some issues. I have 2 tables that together form the third table with the UNION function in DAX. Take a look at tables below:
| Table 1 | ||
| row | ID | amount |
| 1 | 1001 | 10 |
| 2 | 1002 | 10 |
| Table 2 | ||
| row | ID | amount |
| 1 | 1003 | 12 |
| 2 | 1004 | 15 |
| Table 3 | ||
| row | ID | amount |
| 1 | 1001 | 10 |
| 2 | 1002 | 10 |
| 3 | 1003 | 12 |
| 4 | 1004 | 15 |
However, I want the user to be able to first set filters for table 1, then for table 2, and the outcome of both tables should be displayed in table 3. But now, when I filter 1 row from table 1, table 3 also only shows that row. But when I also select a row in table 2, table 3 turns empty.
Is the UNION function the correct one for this? Or is this a relational issue? Would be thankful for the help!
- Anonymous1 year ago
Hi Anonymous ,
If you want to use two filters to display the filtered results on a single table, you first need to make sure that there is no relationship between these two tablesCreate a measure
Is Fittered = IF( SELECTEDVALUE('Table 3'[Row]) IN VALUES('Table 1'[Row]) || SELECTEDVALUE('Table 3'[Row]) IN VALUES('Table 2'[row]), 1, 0 )Apply the measure to the Table 3
Final output
Best regards,
Albert HeIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly
2 Replies
- HotChilliCommunity Champion
"when I filter 1 row from table 1" - where are you doing this?
- AnonymousNot applicable
Hi Anonymous ,
If you want to use two filters to display the filtered results on a single table, you first need to make sure that there is no relationship between these two tablesCreate a measure
Is Fittered = IF( SELECTEDVALUE('Table 3'[Row]) IN VALUES('Table 1'[Row]) || SELECTEDVALUE('Table 3'[Row]) IN VALUES('Table 2'[row]), 1, 0 )Apply the measure to the Table 3
Final output
Best regards,
Albert HeIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly