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NavaneethaRaju's avatar
4 years ago
Solved

Need help with Measure

Hi,

 

I need the measure for comparing measure resultant values like the condition. 

Tag IDSet IDSet DescriptionSystemTag OwnerOrder OwnerUsage TypeNo. Of ProceduresTotal Procedures% Of Usage
1221924.902REVREV TiJPJPUsed485096%
1221924.902REVREV TiJPTSShared2504%


My requirement:

I nead to create a flag in No of procedures, to differentiate Used and Shared values like this.
Only if shared procedure is greated than used procedures, i need to show green flag over there, else i need to show red flag.
I'm dont know about compare the measure resultant values.

 

U = CALCULATE(
[No of Procedures],'Tag Usage Fact'[Usage Type]="Used")

S = CALCULATE(
[No of Procedures],'Tag Usage Fact'[Usage Type]="Shared")

Comp(U&S) = IF([U]<[S],1,0)
 
I wrote a measure like this but result not coming correct.

 

Please advice how to compare this values.

 

  • Hi, NavaneethaRaju 

     

    There is nothing wrong with your method, the formula needs to be modified a little.

    U = CALCULATE([No. Of Procedures], FILTER(ALL('Tag Usage Fact'),[Usage Type]="Used"))
    S = CALCULATE([No. Of Procedures],FILTER(ALL('Tag Usage Fact'),[Usage Type]="Shared"))
    Comp(U&S) = IF([U]<[S],1,0)

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

1 Reply

  • v-zhangti's avatar
    v-zhangti
    Community Support

    Hi, NavaneethaRaju 

     

    There is nothing wrong with your method, the formula needs to be modified a little.

    U = CALCULATE([No. Of Procedures], FILTER(ALL('Tag Usage Fact'),[Usage Type]="Used"))
    S = CALCULATE([No. Of Procedures],FILTER(ALL('Tag Usage Fact'),[Usage Type]="Shared"))
    Comp(U&S) = IF([U]<[S],1,0)

    Is this the result you expect?

     

    Best Regards,

    Community Support Team _Charlotte

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.