Forum Discussion
Multiply values in the column with measures based on another column
Hi everyone,
My task is to multiply values in a column based on the corresponding column with measures regarding to it.
I have 4 measures regarding to the Type column.
MeasureA = 4
MeasureB = 3
MeasureC = 1
MeasureD = 5
Here is an example of the value in a column.
What I want is that I want a matrix showing the type of each set and then also show the value of NumberTypeA*MeasureA + NumberTypeB*MeasureB + NumberTypeC*MeasureC + NumberTypeD*MeasureD separately for each set.
Thank you for your help.
Hi Anonymous,
You can use SWITCH function, just like:
= SWITCH([Type], "A", [Number]*[MeasureA], "B",[Number]*[MeasureB], "C",[Number]*[MeasureC],"D",[Number]*[MeasureD],BLANK() )If you still have some question, please don't hesitate to let me known.
Best Regards,
Link
Is that the answer you're looking for? If this post helps, then please consider Accept it as the solution. Really appreciate!
4 Replies
- selimovd
Most Valuable Professional
Hey Anonymous ,
I have a few questions.
What exactly should MeasureA, MeasureB, MeasureC and MeasureD calculate? From the table you show I could not understand your expected result.
Can you show the result matrix that you want to archive? The description let's room for interpretation and I want to be clear on the output.
Thank you and best regards
Denis Selimovic
- AnonymousNot applicable
According to this, right now I already have 4 measures, but I don't know how to multiply with the values in the number column based on the type column
Thank you for your response!
- v-xulin-mstf
Community Support
Hi Anonymous,
You can use SWITCH function, just like:
= SWITCH([Type], "A", [Number]*[MeasureA], "B",[Number]*[MeasureB], "C",[Number]*[MeasureC],"D",[Number]*[MeasureD],BLANK() )If you still have some question, please don't hesitate to let me known.
Best Regards,
Link
Is that the answer you're looking for? If this post helps, then please consider Accept it as the solution. Really appreciate!
- AnonymousNot applicable
Thank you for your answer!