Forum Discussion
Multiply each filtered value
Hi,
İ want to implement below formula for each month selected. how can i achieve this?
for example;
jan= 0,8 feb =2,4 march=-0,8 --> so first 3 months
(((0,8+1) * (2,4 + 1) * (0,8 +1)) - 1) * 100
thanks
sat125 ,
Create a measure using dax below:
Result = VAR First_Month = SELECTEDVALUE('Table'[Date].[Month]) VAR First_Month_Value = SUMX(FILTER(ALL('Table'), 'Table'[Date].[Month] = First_Month), 'Table'[Value]) VAR Second_Month = MONTH(EDATE(SELECTEDVALUE('Table'[Date]), 1)) VAR Second_Month_Value = SUMX(FILTER(ALL('Table'), MONTH('Table'[Date]) = Second_Month), 'Table'[Value]) VAR Third_Month = MONTH(EDATE(SELECTEDVALUE('Table'[Date]), 2)) VAR Third_Month_Value = SUMX(FILTER(ALL('Table'), MONTH('Table'[Date]) = Third_Month), 'Table'[Value]) RETURN (((First_Month_Value + 1) * (Second_Month_Value + 1) * (Third_Month_Value + 1)) - 1) * 100Community Support Team _ Jimmy Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
3 Replies
- amitchandakSuper User
What is 0,8. Problem statement is not very clear
- sat125Frequent Visitor
Hi,
İm trying to calculate the inflation ratio of the months selected so in this case ratio from january to march but im unable to do it with multiply quick measure. when i use it it multiplies the first selected month with itself for example 0,8 *0,8* 2,4 * -0,8
but i need it to multiply for the each month selected from month slicer.
- v-yuta-msftCommunity Support
sat125 ,
Create a measure using dax below:
Result = VAR First_Month = SELECTEDVALUE('Table'[Date].[Month]) VAR First_Month_Value = SUMX(FILTER(ALL('Table'), 'Table'[Date].[Month] = First_Month), 'Table'[Value]) VAR Second_Month = MONTH(EDATE(SELECTEDVALUE('Table'[Date]), 1)) VAR Second_Month_Value = SUMX(FILTER(ALL('Table'), MONTH('Table'[Date]) = Second_Month), 'Table'[Value]) VAR Third_Month = MONTH(EDATE(SELECTEDVALUE('Table'[Date]), 2)) VAR Third_Month_Value = SUMX(FILTER(ALL('Table'), MONTH('Table'[Date]) = Third_Month), 'Table'[Value]) RETURN (((First_Month_Value + 1) * (Second_Month_Value + 1) * (Third_Month_Value + 1)) - 1) * 100Community Support Team _ Jimmy Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.