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Anonymous
Not applicable

Monthly Cumulative sum of bugs by priority wise

Hi Team,

 

I need yout help to get monthly cumulative count of Open Bugs by priority wise.

 

Here the problem is Bug is in Workitem type Column, Open is in State of the task column, Month is in Created date column and Priority is in Priority column.

 

Thanks in Advance.

1 ACCEPTED SOLUTION
v-janeyg-msft
Community Support
Community Support

Hi,  @Anonymous 

 

You need to put the create date as a slicer or use table visual to show results.

measure =
CALCULATE (
    COUNTROWS ( 'table' ),
    table[workitem] = "Bug",
    table[state] = "Open",
    MONTH ( table[create date] ) = MONTH ( SELECTEDVALUE ( table[create date] ) ),
    table[priority] = "priority"
)

If it doesn’t solve your problem, please feel free to ask me.

 

Best Regards

Janey Guo

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
v-lionel-msft
Community Support
Community Support

Hi @Syndicate_Admin ,

 

Please provide sample data and explain the sample data.

 

Best regards,
Lionel Chen

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

sayaliredij
Solution Sage
Solution Sage

It is not clear enough. 

 

Could you provide small sample data?





Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




v-janeyg-msft
Community Support
Community Support

Hi,  @Anonymous 

 

You need to put the create date as a slicer or use table visual to show results.

measure =
CALCULATE (
    COUNTROWS ( 'table' ),
    table[workitem] = "Bug",
    table[state] = "Open",
    MONTH ( table[create date] ) = MONTH ( SELECTEDVALUE ( table[create date] ) ),
    table[priority] = "priority"
)

If it doesn’t solve your problem, please feel free to ask me.

 

Best Regards

Janey Guo

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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